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kirill [66]
3 years ago
6

Solve for x please help with this one too​

Mathematics
1 answer:
otez555 [7]3 years ago
5 0

Answer:    7

Step-by-step explanation:

Here, two chords of the circle is intersecting outside the given circle.

Thus, By the intersecting chord outside the circle theorem,

(x+5)\times 5=10\times 6

(x+5)\times 5=60

x+5=12

x =12-5

x =7

Hence, the value of x is 7.

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ivolga24 [154]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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A parallelogram has sides 10m and 12m and an angle of 45°. Find the distance between the 12m-sides.
stich3 [128]

Answer:

The distance between 12m-sides is 5\sqrt{2}m.

Step-by-step explanation:

It is given that the parallelogram has sides 10m and 12m and an angle of 45°.

Draw an altitude from one 12m side to another 12 m side as shown in below figure.

The opposite angles of parallelogram are same. Two angles are obtuse angles and two are acute angle.

Since angle C is acute angle therefore it must be 45 degree.

\sin\theta=\frac{perpendicular}{hypotenuse}

\sin C=\frac{BE}{BC}

\sin(45^{\circ})=\frac{d}{10}

\frac{1}{\sqrt{2}}=\frac{d}{10}

\frac{10}{\sqrt{2}}=d

\frac{10}{\sqrt{2}}\times \frac{\sqrt{2}}{\sqrt{2}}=d

\frac{10\sqrt{2}}{2}=d

5\sqrt{2}=d

Therefore the distance between 12m-sides is 5\sqrt{2}m.

4 0
3 years ago
PLEASE HELP
Makovka662 [10]

The answer is -3 on apex:)

4 0
3 years ago
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a clerk is paid $45.25 per hours for 40 hours a week, 1.50 times the regular rate of overtime and double the rate for a holiday.
KonstantinChe [14]

Given :

A clerk is paid $45.25 per hours for 40 hours a week, 1.50 times the regular rate of overtime and double the rate for a holiday.

To Find :

How much does the clerk get if he works overtime for 5 hours and 2 hours on holidays.

Solution :

Amount from regular job = $ 45.25 × 40 = $1810 .

Amount from overtime = $ (45.25×1.5) × 5 = $339.375 .

Amount from holiday = $ (45.25×2) × 5 = $452.5 .

Total amount clerk will get is :

T = $( 1810 + 339.375 + 452.5 )

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Hence, this is the required solution.

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3 years ago
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Answer:

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