F(x) = 2x + 2.....find f(3)
f(3) = 2(3) + 2
f(3) = 6 + 2
f(3) = 8
f(x) = (3x - 4)/5....find f^-1(4)
y = (3x - 4)/5...swap the variables
x = (3y - 4)/5 ...solve for y
5x = 3y - 4
5x + 4 = 3y
(5x + 4)/3 = y
f^-1(x) = (5x + 4)/3.....for f(4)
f(4) = (5(4) + 4)/3
f(4) = (20 + 4)/3
f(4) = 24/3
f(4) = 8
y + 10 = 2y + 1
y - 2y = 1 - 10
-y = -9
y = 9
so 1 and 2 have the same result...8
The answer would be 280 because 28x10 is 280
Sorry I would have helped but just now seen this. Hope you got it correct
Answer:
c.
Step-by-step explanation:
2 lines are cut by a transversal. At the intersection of the first line with the transversal, the bottom right angle is 130 degrees. At the intersection of the second line with the transversal, the uppercase right angle is 50 degrees.
1. 21f+42
2.36 - 8f
3. 40-5f
