Answer:
The side closest to P is the side that is on the same side of the angle bisector as P.
Step-by-step explanation:
The angle bisector is the line containing all the points equidistant from the sides of the angle. Points on one side of the angle bisector are closer to the angle side that is on that side of the angle bisector.
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The attached diagram shows the angle bisector as a dashed line. A couple of different locations for P are shown (P1 and P2). Apparently, we're concerned here with the distance from P along the perpendicular to each side of the angle. For P2 (on the left side of the angle bisector), it may be clear that the left perpendicular is shorter than the right one. Likewise, for P1, the right perpendicular will be shorter.
 
        
             
        
        
        
Hey there! 
Which is the prime factorization of 40?
Option A.
2 * 5
= 2 + 2 + 2 + 2 + 2
= 4 + 4 + 2
= 8 + 2
= 10
Option B.
2^3 * 5
= 2 * 2 * 2 * 5
= 4 * 2 * 5
= 8 * 5
= 40 
Option C.
2 * 53
= 53 * 2
= 53 + 53
= 106
2 * 3 * 5
= 6 * 5
= 6 + 6 + 6 + 6 + 6
= 12 + 12 + 6
= 24 + 6
= 30
Therefore, your answer is: 
Option B. 2^3 * 5
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
 
        
             
        
        
        
Answer:
1 and 2/5 yards wastes only 1/15 a yard
Step-by-step explanation:
1 and 1/6 yards  would make a waste of 1 and 1/6 yards since you can't make a ribbon out of it. (incorrect)
1 and 2/10 yards  would make a waste of 1 and 1/5 yards since you can't make a ribbon out of it. (incorrect)
1 and 2/5 yards

Wastes 1/15 a yard.
1 and 1/2 yards  

It wastes 1/6 a yard.
2 yards

It wastes 4/6 a yard.
 
        
             
        
        
        
Answer:
FALSE
Step-by-step explanation:
In order to be consistent with the system of unit we should decide if we are going to work with the CGS system <em>(centimeter-gram-second)</em> or the MKS system <em>(meter-kilogram-second).
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If we decide to work with the CGS system, the equation of motion would be
8,000x ′′ + 2x = 0; x(0) = 3, x ′ (0) = 0
since 1 Kg = 1,000 g
If we decide to work with the MKS system, the equation of motion would be
8x ′′ + 2x = 0; x(0) = 0.03, x ′ (0) = 0
given that 1 mt = 100 cm