The expression is
5x + 5y
We are to prove that it is an odd integer when x and y are integers of opposite parity
First, we can assume
x = 2a (even)
y = 2b + 1(odd)
subsituting
10(a + b) + 5
5 [(2(a + b) + 1]
The term
2(a + b) + 1 is odd and the result of an odd number multiplied by an odd number is odd
Answer:
D
Step-by-step explanation:
3 - 7 = -4 and 3(3) + 2(-7) = -5, so D is the only choice that is correct for both inequalities.
Domain is all the possible inputs of an equation. In this example, the only concern is the x + 5 because the denominator cannot equal 0 because we can't divided by 0. So we set x + 5 equal to zero and solve for x.
x + 5 = 0
x = -5
The restriction is that x cannot equal -5.
Answer:
3(4a−5b+2)
Step-by-step explanation:
The answer should have originally been 3(4a-5b+2)
3(4a+5b+3)= 12a+15b+9 which is incorrect.