A boy pushes on box of mass 43 kg and it moves at an acceleration of 8.6m/s

Mathematics

2 answers:

madam [21]3 years ago

7 0

If you want to work out the force then F=MA, therefore 43*8.6=369.8 Newtons

zavuch27 [327]3 years ago

5 0

I Would Say Yes, She Basically Stole My Answer That She Answered... [ xD ]

You might be interested in

How do I find the slope intercept

gavmur [86]

Use the slope intercept form; y=mx+b where m is the slope and b is the y-intercept

5 0

3 years ago

Please Help me with my Math question!

iris [78.8K]

C= 8x + 5y
y-number of child tikets
C-8x= 5y
(C-8x)/5 =y
First option from up to down

8 0

3 years ago

Read 2 more answers

Find the Area of the Shaded Region.

Mrac [35]

9514 1404 393

Answer:

610 m²

Step-by-step explanation:

If we extend the horizontal line across the right-hand portion of the figure, then the figure is divided into two rectangles:

bottom: 5 m × 50 m = 250 m²

top: 18 m × 20 m = 360 m²

The sum of these areas is the shaded area:

shaded area = 250 m² +360 m² = 610 m²

4 0

2 years ago

Given: m<4 + m<7 = 180°<br> Prove: c ll d<br> I need the statements and reasons

AVprozaik [17]

The horses name was friday

6 0

2 years ago

Read 2 more answers

Can you work out G and H for me please. preferably telling me how you did it aswell

Veronika [31]

Abd is a right angled triangle so by pythagoras we know
${g}^{2} = {11}^{2} + {13}^{2} \\ {g}^{2} = 290 \\ g = \sqrt{290} \: or \: g = 17.03cm$
and to calculate h we need to use the sine rule
$\frac{h}{ \sin(22) } = \frac{g}{ \sin(32) } \\ \frac{h}{ \sin(22) } = \frac{17.03}{ \sin(32) } \\ h = \frac{17.03}{ \sin(32) } \times \sin(22) \\ h = 12.04cm$
i hope this helps

8 0

3 years ago