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3 years ago

A boy pushes on box of mass 43 kg and it moves at an acceleration of 8.6m/s

Mathematics

2 answers:

madam [21]3 years ago

7 0

If you want to work out the force then F=MA, therefore 43*8.6=369.8 Newtons

zavuch27 [327]3 years ago

5 0

I Would Say Yes, She Basically Stole My Answer That She Answered... [ xD ]

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astra-53 [7]

Answer:

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Step-by-step explanation:

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3 years ago

Which statement is always true? A.) The absolute value of an integer is equal to the opposite of the integer B.) a positive inte

Ahat [919]

Answer:

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3 years ago

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Bogdan [553]

Answer:

$\boxed{x$

Step-by-step explanation:

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3 years ago

Convert 3<br> 8 into a decimal.

marishachu [46]

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Step-by-step explanation:

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2 years ago

Prove whether the following are identities 2tanh 1/2x / 1−tanh^2 1/2 x = sinh x

Tanzania [10]

Recall that

$\cosh^2(x) - \sinh^2(x) = 1$

Dividing both sides by cosh²(x) gives

$1 - \tanh^2(x) = \mathrm{sech}^2(x)$

Also, recall the identity

$\sinh(2x) = 2\sinh(x)\cosh(x)$

Then

$\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \dfrac{2\tanh\left(\frac x2\right)}{\mathrm{sech}^2\left(\frac x2\right)} \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\tanh\left(\dfrac x2\right)\cosh^2\left(\dfrac x2\right) \\\\ \dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = 2\sinh\left(\dfrac x2\right)\cosh\left(\dfrac x2\right) \\\\\dfrac{2\tanh\left(\frac x2\right)}{1 - \tanh^2\left(\frac x2\right)} = \sinh(x)$

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3 years ago