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4 years ago

What is the solution to the system of equations represented by the two equations?

Mathematics

1 answer:

FinnZ [79.3K]4 years ago

4 0

Make the two equations equal together and solve for x
(x/3) = -2x+7
multiple both sides by 3
x=-6x+21
solve for x
7x=21
x=3.
now plug in 3 into one of the equation to find your y value.
y=-2(3)+7
y=1
write your answer as a coordinate; (3,1)

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Order the angles in each triangle from smallest to largest. NO LINKS!!!!

lakkis [162]

Answers:

Problem 13) M, N, L
Problem 14) N, L, M

For each answer above, the angles are sorted from smallest to largest.

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Explanation:

The general rule used here is: the smallest side is always opposite the smallest angle. Similarly, the largest side is always opposite the largest angle. This trick only works for triangles.

For problem 13, the smallest angle is M because the shortest side is opposite this angle (side NL = 12). The largest side is MN = 21, making the angle opposite this (angle L) to be the largest angle.

We do not need to compute the actual angle values, though you could if you wanted. To find the angle values, you would use the law of cosines. The steps for this are fairly lengthy, so I'll just use the trick mentioned above.

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Problem 14 is the same idea. Here LM = 7 is the shortest side this time, leading to angle N as the opposite angle that's the smallest of the three angles. Angle M is the largest angle because NL = 14 is the longest side.

8 0

3 years ago

Read 2 more answers

There are 9 students in a class: 2 boys and 7 girls. If the teacher picks a group of 4 at random, what is the probability that e

notsponge [240]

Answer:

<h2>28% probability that every student in the group is a girl.</h2>

Step-by-step explanation:

In this problem we have independent events, that is, the event "picking a girl" doesn't affect an "picking a boy", also, picking picking a girl doesn't affect the probability of the other subjects.

So, the probability when the first girl is being picked is:

$P_{1}=\frac{7 \ girls}{9 \ students}$

Because among the total 9 students, there are 7 girls.

Now, after picking one girl, there remains 6 girls and 8 students to be picked. So, the probability of the second girl would be:

$P_{2}=\frac{6 \ girls}{8 \ students}$

Then, the probability of the third girl:

$P_{3}=\frac{5 \ girls}{7 \ students}$

The fourth girl probability:

$P_{3}=\frac{4 \ girls}{6 \ students}$

Therefore, the probability of picking all 4 girls would be the product of each probability, because events are independent (we use product when they are independent):

$P=\frac{7 \ girls}{9 \ students} \times \frac{6 \ girls}{8 \ students} \times \frac{5 \ girls}{7 \ students} \times \frac{4 \ girls}{6 \ students}\\P=\frac{5}{18}=0.28 \ (or \ 28\%)$

Therefore, there's 28% probability that every student in the group is a girl.

5 0

3 years ago

Graph the system of equations, and determine the solution.<br> x+5y=5<br> 2x+10y=60

Step2247 [10]

Step-by-step explanation:

the systems have no solution

the lines are parallel each other

graph as attached

3 0

3 years ago

Use rounding to estimate the product of 5, 555 and 4, 444. Round both numbers to the nearest thousand to find your answer.

uranmaximum [27]

Step-by-step explanation:

5,555 can be rounded up to 6,000 because the 5 next to the five thousand will make it go up. while the 4,444 will round to 4,000 . I don't have a clear answer but I hope this helps.

8 0

3 years ago

At the start of the day there was 129.75 in the till one hour later there is 145.40 how much did the shop take in a hour

777dan777 [17]

At the start of the day, there was £129.75. Later, they made more money, so the <span>£145.50. To find the amount of change, you just need to deduct the number 129.75 from 145.50.

145.50 - 129.75 = 15.75

The shop made </span><span>£15.75 in one hour.</span>

8 0

4 years ago