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3 years ago

Section 1 - Question 9

Mathematics

1 answer:

Neko [114]3 years ago

6 0

The answer to this question is B

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Compare the decimals 0.29__0.3

Nostrana [21]

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=
Are the answers the first line is for the first question same for the second and 3rd

7 0

4 years ago

Can you please help with 19&23? 19 says write an expression to represent the perimeter. Thanks!

Valentin [98]

the perimeter is simply the sum of all its sides.

(6a+8)+(12a)+(6a+8)+(10a-4)

34a + 16 - 4

34a + 12.

7 0

3 years ago

9/20

Stella [2.4K]

Question:

Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0

Answer:

The number of real solutions for the equation $x^{2}+5 x+7=0$ is zero

Solution:

For a Quadratic Equation of form : $a x^{2}+b x+c=0$ ---- eqn 1

The solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Now , the given Quadratic Equation is $x^{2}+5 x+7=0$ ---- eqn 2

On comparing Equation (1) and Equation(2), we get

a = 1 , b = 5 and c = 7

In $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ , $b^2 - 4ac$ is called the discriminant of the quadratic equation

Its value determines the nature of roots

Now, here are the rules with discriminants:

1) D > 0; there are 2 real solutions in the equation

2) D = 0; there is 1 real solution in the equation

3) D < 0; there are no real solutions in the equation

Now let solve for given equation

$D= b^2 - 4ac\\\\D = 5^2 - 4(1)(7)\\\\D = 25 - 28 \\\\D = -3$

Since -3 is less than 0, this means that there are 0 real solutions in this equation.

4 0

4 years ago

The number 0.0002 is 1/10 of

Ratling [72]

Answer:

I think it is 0.002

6 0

3 years ago

Read 2 more answers

12/19*.............................= -12/19

melamori03 [73]

Answer:

$\frac{12}{19} \times \underline{\bold{-1}} = -\frac{12}{19}$

Step-by-step explanation:

$\frac{12}{19} \times ..... = -\frac{12}{19}$

= $\frac{\frac{12}{19}}{-\frac{12}{19}}$

= $\frac{12}{19} \times -\frac{19}{12}$

= $-\frac{228}{228}$

= $\bold{-1}$

So, the appropriate value to complete it is -1

#CMIIW ^^

3 0

4 years ago