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Kazeer [188]
3 years ago
10

Syrus is buying a tent with the dimensions shown below. The volume inside the tent is 36 feet. Syrus isn't sure if the tent will

be tall enough for him to sit up inside. What is the height of the tent?
Mathematics
2 answers:
ivolga24 [154]3 years ago
7 0

Answer:

the answer is 3 feet

Step-by-step explanation:

We can use the volume formula, V =1/2 bhl to find the height of the tent

the volume is 36^{3}. The base is 4 and the length is 6 feet

​36=1/2 ⋅4⋅h⋅6

36=12h

3=h

The height of <em>the tent is 3 feet.</em>

nataly862011 [7]3 years ago
4 0

Answer:

The height of the tent is 3 feet

Step-by-step explanation:

Using the equation V(volume): 1/2*b(base)*h(height)*l(length)

We know this..

36 is the volume

4 is the base

6 is the length

36=1/2 * 4 *h * 6

36=12h

We want to get h by itself so we divide.

36/12 = 3

12h/12 = h

3=h

In conclusion, the height of the tent is 3 feet.

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Help me with this question
Colt1911 [192]

Step-by-step explanation:

just look at the graphic : what value do we have on the cost side, when we have 1 pounds on the amount side ?

all the answer options specify a price per pound. that is why we only need to focus on the price for one pound.

we see in the graphic, that for 1 pound the price is $4.

just to make sure, we can also work with the directly specified point (0.5, 2), which means that 0.5 pounds cost $2.

and the function is clearly a straight line.

so, every point on the function has the same y/x ratio (slope).

therefore,

2/0.5 = 4

now, what point with x=1 has the same ratio ?

y/1 = 4

y = $4

perfect, the results are identical. so, $4 per pound is the correct answer.

4 0
3 years ago
2(3/5n +3) - (2/3n-1)
borishaifa [10]

Hey there! :)


2(3/5n + 3) - (2/3n - 1)


Simplify.


(2 * 3/5n) + (2 * 3) - (2/3n -1)


Simplify.


6/5n + 6 - 2/3n + 1


Add like terms.


(6/5n - 2/3n) + (6 + 1)


Make the fractions have the same denominator by multiplying fraction 1 (6/5n) by 3/3 and fraction 2 (-2/3n) by 5/5.


6/5n * 3/3 = 18/15n


-2/3n * 5/5 = -10/15n


So, our new equation looks like this : (18/15n - 10/15n) + (6 + 1)


Simplify.


8/15n + 6 —> final answer.


Hope this helped! :)

4 0
3 years ago
Read 2 more answers
Theo recorded the means and mean absolute deviations of his language arts and Biology scores. He found the difference in the mea
Rina8888 [55]

The answer is actually A.2 because I just took the test.

8 0
4 years ago
Read 3 more answers
Each day a commuter takes a bus to work, the transportation system has a phone app that tells her what time the bus will arrive.
Paraphin [41]

Answer:

Step-by-step explanation:

Hello!

The commuter is interested in testing if the arrival time showed in the phone app is the same, or similar to the arrival time in real life.

For this, she piked 24 random times for 6 weeks and measured the difference between the actual arrival time and the app estimated time.

The established variable has a normal distribution with a standard deviation of σ= 2 min.

From the taken sample an average time difference of X[bar]= 0.77 was obtained.

If the app is correct, the true mean should be around cero, symbolically: μ=0

a. The hypotheses are:

H₀:μ=0

H₁:μ≠0

b. This test is a one-sample test for the population mean. To be able to do it you need the study variable to be at least normal. It is informed in the test that the population is normal, so the variable "difference between actual arrival time and estimated arrival time" has a normal distribution and the population variance is known, so you can conduct the test using the standard normal distribution.

c.

Z_{H_0}= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } }

Z_{H_0}= \frac{0.77-0}{\frac{2}{\sqrt{24} } }= 1.89

d. This hypothesis test is two-tailed and so is the p-value.

p-value: P(Z≤-1.89)+P(Z≥1.89)= P(Z≤-1.89)+(1 - P(Z≤1.89))= 0.029 + (1 - 0.971)= 0.058

e. 90% CI

Z_{1-\alpha /2}= Z_{0.95}= 1.645

X[bar] ± Z_{1-\alpha /2}* (\frac{Sigma}{\sqrt{n} } )

0.77 ± 1.645 * (\frac{2}{\sqrt{24} } )

[0.098;1.442]

I hope this helps!

4 0
3 years ago
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Greeley [361]
The first graph shows that equation.
5 0
4 years ago
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