Answer:
![62\ in^2](https://tex.z-dn.net/?f=62%5C%20in%5E2)
Step-by-step explanation:
we know that
The area of the composite figure is equal to the area of a right triangle plus the area of rectangle
see the attached figure to better understand the problem
step 1
Find the area of the right triangle
we know that
The area of triangle is
![A=\frac{1}{2}(b)(h)](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%28b%29%28h%29)
where
![b=7-4=3\ in\\h=12-8=4\ in](https://tex.z-dn.net/?f=b%3D7-4%3D3%5C%20in%5C%5Ch%3D12-8%3D4%5C%20in)
substitute
![A_1=\frac{1}{2}(3)(4)=6\ in^2](https://tex.z-dn.net/?f=A_1%3D%5Cfrac%7B1%7D%7B2%7D%283%29%284%29%3D6%5C%20in%5E2)
step 2
Find the area of rectangle
The area of rectangle is equal to
![A=LW](https://tex.z-dn.net/?f=A%3DLW)
where
![L=8\ in\\W=7\ in](https://tex.z-dn.net/?f=L%3D8%5C%20in%5C%5CW%3D7%5C%20in)
substitute
![A_2=(8)(7)=56\ in^2](https://tex.z-dn.net/?f=A_2%3D%288%29%287%29%3D56%5C%20in%5E2)
step 3
Find the area of the composite figure
Adds the areas
![A=A_1+A_2](https://tex.z-dn.net/?f=A%3DA_1%2BA_2)
![A=6+56=62\ in^2](https://tex.z-dn.net/?f=A%3D6%2B56%3D62%5C%20in%5E2)
Answer:
Part 1: f(x)=0 has 0 solutions
Part 2: g(x)=0 has 2 solutions
Part 3: h(x)=0 has 1 solution
I graphed them
Answer:
hmm. i will say the answer is option B
Answer:
26%
Step-by-step explanation:
10/39 + 100% = 25.64102%
nearest percent, 26%
Jack has 212 marbles.
Step-by-step explanation:
Jack and Watson have = 365 marbles
Jack and Asher have = 263 marbles
Let,
x be the marbles Jack have
y be the marbles Watson have
z be the marbles Asher have
According to given statement;
x+y=365 Eqn 1
x+z=263 Eqn 2
Watson has three times as many marbles is Asher.
y=3z Eqn 3
Putting y=3z in Eqn 1;
x+3z=365 Eqn 4
Subtracting Eqn 2 from Eqn 4
![(x+3z)-(x+z)=365-263\\x+3z-x-z=102\\2z=102](https://tex.z-dn.net/?f=%28x%2B3z%29-%28x%2Bz%29%3D365-263%5C%5Cx%2B3z-x-z%3D102%5C%5C2z%3D102)
Dividing both sides by 2
![\frac{2z}{2}=\frac{102}{2}\\z=51](https://tex.z-dn.net/?f=%5Cfrac%7B2z%7D%7B2%7D%3D%5Cfrac%7B102%7D%7B2%7D%5C%5Cz%3D51)
Putting z=51 in Eqn 2
![x+51=263\\x=263-15\\x=212](https://tex.z-dn.net/?f=x%2B51%3D263%5C%5Cx%3D263-15%5C%5Cx%3D212)
Jack has 212 marbles.
Keywords: linear equations, subtraction
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