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slava [35]
3 years ago
14

What is the solution to this system of linear equations?2x + y = 13x – y = –6(–1, 3)(1, –1)(2, 3)(5, 0)

Mathematics
1 answer:
worty [1.4K]3 years ago
5 0

\underline{+\left\{\begin{array}{ccc}2x+y=1\\3x-y=-6\end{array}\right}\ \ \ \ |\text{add both sides of equations}\\.\ \ \ \ \ 5x=-5\ \ \ \ |:5\\.\ \ \ \ \ \ x=-1\\\\\text{put the value of x to the first equation}\\\\2(-1)+y=1\\-2+y=1\ \ \ |+2\\y=3\\\\\text{Answer:}\ (-1,\ 3)

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Answer:

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Step-by-step explanation:

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Deepak wrote out the steps to his solution of the equation startfraction 5 over 2 minus 3 x minus 5 plus 4 x equals negative sta
andre [41]

The solution is x=3/4

How can we solve given equation?

First, we will solve like terms. Then shift constant to other side and keep x on the same side to get the value of x.

We can solve given equation as shown below:

5/2-3x-5+4x=-7/4

(5-10)/2+x=-7/4

-5/2+x=-7/4

x=5/2-7/4

x= (10-7)/4

x=3/4

Hence, the solution is x=3/4.

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3 years ago
is (-1/2 x + 6/7) - (7/2 x - 4/7) equivalent to -4 x + 2/7 ? use the properties of operations to justify your answer
LuckyWell [14K]

Answer:

The given equation is NOT justified.

Step-by-step explanation:

Here, the given equation is (\frac{-1}{2}x + \frac{6}{7} )  -  (\frac{7}{2}x - \frac{4}{7} )   = -4x + \frac{2}{7}

Now, here Consider the left hand side and simplifying the left side by operating on the like terms,

⇒(\frac{-1}{2}x + \frac{6}{7} )  -  (\frac{7}{2}x - \frac{4}{7} )   = \frac{-1}{2}x + \frac{6}{7}   -  \frac{7}{2}x + \frac{4}{7}  =  (\frac{-1}{2}x -\frac{7}{2}x) + (\frac{6}{7}   + \frac{4}{7})

=(\frac{-1 - 7}{2}x ) + (\frac{6 + 4}{7} ) = \frac{-8x}{2} + \frac{10}{7}   \neq -4x + \frac{2}{7}

Here, Left side of equation  ≠ Right side of the equation

Hence, (\frac{-1}{2}x + \frac{6}{7} )  -  (\frac{7}{2}x - \frac{4}{7} )   ≠ -4x + \frac{2}{7}

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3 years ago
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