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shutvik [7]
3 years ago
9

Which domain of an IT infrastructure primarily includes the processes and procedures that end users use to remotely access an or

ganization's IT infrastructure and data?
Computers and Technology
1 answer:
Natalka [10]3 years ago
6 0

Answer:

The answer is "Remote Domain Access".

Explanation:

It is also known as web access, it is an opportunity to moderately access a desktop or network over a connection to the internet. It also allows you to download the structures, that want even if they are not mentally and emotionally able to communicate specifically.

  • In other words, it uses a satellite for interaction or internet service, and users can access systems remotely.
  • It is also used in the database, that's why it is the correct answer.
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Which font attribute would be most appropriate to make a papers heading stand out?
eimsori [14]

If you want your heading to pop out I would go for bold Becuase it shows the letters darker and bigger which would make the heading the center of attention.

7 0
3 years ago
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Which of the following is a basic principle of improvement?
lesya [120]

From the given the statement, "every system is perfectly designed to get the results it gets" is a basic principle of improvement.

Option B

<u>Explanation:</u>

The improvement activity begins with the quote ‘every system is perfectly designed to get the results it gets’, by W. Edwards Deming; The quote states both the unintended and intended effects are designed into our systems.

For example: Healthcare in the UK has been perfectly designed to lower the waiting times to 18 weeks for various procedures over last twelve years. Reflecting on Safer Patients Initiative (SPI), this can be true to improvement systems: every improvement system is perfectly designed to get the results its gets and SPI is a case in point.

The leading improvements that need to be designed into our improvement systems:

  • Improvement activity needs to be built on strong foundations
  • Greater engagement with people’s intrinsic motivation
  • Embrace a wider set of methods
  • Greater understanding of how systems and processes outside direct clinical care contribute to safety and quality.

So, it can be concluded that the line given by W. Edwards Deming tends to be the principle of improvement.

6 0
3 years ago
What is the purpose of a web server? What is the purpose of a web browser?
Sauron [17]

Answer: the purpose of a web browser is to help answer and needed questions, and to get to sites.

Explanation:

4 0
2 years ago
Develop a plan to design and finally implement a set of functions using C++ that would implement the IEEE standard. Phase 1 will
AnnZ [28]

Answer:

See explaination code

Explanation:

#include<iostream>

#include<math.h>

using namespace std;

typedef union {

float number;

struct

{

// Order is important.

// Here the members of the union data structure

// use the same memory (32 bits).

// The ordering is taken

// from the LSB to the MSB.

unsigned int mantissa : 23;

unsigned int exponent : 8;

unsigned int sign : 1;

} Raw;

} MyFloat;

void printBinary(int n, int i)

{

// Prints the binary representation

// of a number n up to i-bits.

int k;

for (k = i - 1; k >= 0; k--) {

if ((n >> k) & 1)

cout << "1";

else

cout << "0";

}

}

void decToHex(int n){

// char array to store hexadecimal number

char hexaDeciNum[100];

// counter for hexadecimal number array

int i = 0;

while(n!=0)

{

// temporary variable to store remainder

int temp = 0;

// storing remainder in temp variable.

temp = n % 16;

// check if temp < 10

if(temp < 10)

{

hexaDeciNum[i] = temp + 48;

i++;

}

else

{

hexaDeciNum[i] = temp + 55;

i++;

}

n = n/16;

}

// printing hexadecimal number array in reverse order

for(int j=i-1; j>=0; j--)

cout << hexaDeciNum[j];

}

void floatBinary(float f){

long double binaryTotal, binaryFrac = 0.0, frac, fracFractor = 0.1;

long int integer, binaryInt = 0;

long int p = 0, rem, temp;

//separate the integer part from the input floating number

integer = (int)f;

//separate the fractional part from the input floating number

frac = f - integer;

//loop to convert integer part to binary

while (integer != 0) {

rem = integer % 2;

binaryInt = binaryInt + rem *pow(10, p);

integer = integer / 2;

p++;

}

//loop to convert fractional part to binary

while (frac != 0) {

frac = frac * 2;

temp = frac;

binaryFrac = binaryFrac + fracFractor * temp;

if (temp == 1)

frac = frac - temp;

fracFractor = fracFractor / 10;

}

cout << binaryInt + binaryFrac;

}

int findDecimal(float number){

int nfloor = number;

float nfloat = number - nfloor;

int nfloatfloor;

do {

nfloat *= 10;

nfloatfloor = nfloat;

} while (nfloat > nfloatfloor);

return nfloatfloor;

}

void first(float number){

if(number < 0)

cout << "SIGN BIT IS (1) SINCE NUMBER IS NEGATIVE" << endl;

else

cout << "SIGN BIT IS (0) SINCE NUMBER IS POSITIVE" << endl;

}

void second(float number){

cout << "INTEGER PART IN BASE-10:" << int(number) << " AND IN BINARY:";

printBinary(int(number),16);

cout << endl;

}

void third(float number){

cout << "DECIMAL PART IN BASE-10:" << findDecimal(number) << " AND IN BINARY:";

printBinary(findDecimal(number),16);

cout << endl;

}

void fourth(float number){

cout << "ENTERED NUMBER IN BASE-10:" << number << " AND IN BINARY:";

floatBinary(number);

cout << endl;

}

void fifth(MyFloat myfloat){

cout << "MANTISA IN BINARY:";

printBinary(myfloat.Raw.mantissa,32);

}

void sixth(MyFloat myfloat){

cout << "EXPONENT IN BASE-10:" << myfloat.Raw.exponent << " AND IN BINARY:";

printBinary(myfloat.Raw.exponent,8);

cout << endl;

}

void seventh(MyFloat myfloat){

cout << myfloat.Raw.sign << " | ";

printBinary(myfloat.Raw.exponent,8);

cout << " | ";

printBinary(myfloat.Raw.mantissa,32);

cout << endl;

}

void eigth(MyFloat myfloat){

cout << myfloat.Raw.sign << " | ";

decToHex(myfloat.Raw.exponent);

cout << " | ";

decToHex(myfloat.Raw.mantissa);

cout << endl;

}

int main(){

float number;

cout << "PLEASE ENTER A NUMBER TO DISPLAY THE IEEE 754 FLOATING POINT OPTIONS" << endl;

cin >> number;

MyFloat myfloat;

myfloat.number = number;

cout << "PLEASE CHOOSE ONE OF THE FOLLOWING OPERATIONS" << endl;

cout << " 1. DISPLAY THE SIGN BIT VALUE" << endl;

cout << " 2. DISPLAY THE INTEER PART IN BOTH BASE-10 AND CINARY FORMATS" << endl;

cout << " 3. DISPLAY THE DECIMAL PART IN BOTH BASE-10 AND BINARY FORMATS" << endl;

cout << " 4. DISPLAY THE NUMBER ENTERED IN BOTH BASE-10 AND BINARY FORMATS" << endl;

cout << " 5. DISPLAY THE MANTISA IN BINARY FORMATS" << endl;

cout << " 6. DISPLAY THE EXPONENT IN BORH BASEE-10 AND BINARY FORMATS" << endl;

cout << " 7. DISPLAY THE IEEE 754 SINGLE PRECISION BINARY LAYOUT" << endl;

cout << " 8. DISPLAY THE IEEE 754 SINGLE PRECISION BINARY LAYOUT" << endl;

int choice;

cin >> choice;

switch(choice){

case 1:first(number);

break;

case 2:second(number);

break;

case 3:third(number);

break;

case 4:fourth(number);

break;

case 5:fifth(myfloat);

break;

case 6:sixth(myfloat);

break;

case 7:seventh(myfloat);

break;

case 8:eigth(myfloat);

break;

default:cout << "ENTER VALID CHOICE" << endl;

}

}

Refer to attachment please for onscreen look.

6 0
3 years ago
The total nodal delay includes:
blondinia [14]

Answer:

all of the above

Explanation:

Total nodal delay is the sum of all types of delay.There are basically four types delay that are as following:-

  1. Processing Delay.
  2. Propagation Delay.
  3. Transmission Delay.
  4. Queuing Delay.

T(nodal)=T(processing)+T(propagation)+T(transmission)+T(queuing).

Where T is the delay time.We are given with propagation,transmission and processing.Nodal delay includes these 3 delays.

Hence we conclude that the answer is all of the above.

3 0
3 years ago
Read 2 more answers
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