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Valentin [98]
3 years ago
11

While doing research on the Internet, what kind of website should you avoid because the information may be biased?

Computers and Technology
1 answer:
Alexeev081 [22]3 years ago
5 0
Most likely blogs, because these are what people write on for personal reasons
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Copyright ownership analysis starts with this principle: The ________ is the owner.
pogonyaev

Answer: Author

Explanation: self explanatory

3 0
3 years ago
Write a zip code class that encodes and decodes 5-digit bar codes used by the U.S. Postal Service on envelopes. The class should
8_murik_8 [283]

Answer:

#include<iostream>

#include<string>

using namespace std;

class zip_code

{

private:

int zipcode;

string get_string(int num)

{

string str="";

if(num == 0) return "11000";

if(num>7)

{

str.append("1");

num = num-7;

}

else

str.append("0");

if(num>4)

{

str.append("1");

num = num-4;

}

else

str.append("0");

if(num>2)

{

str.append("1");

num = num-2;

}

else

str.append("0");

if(num>1)

{

str.append("1");

num = num-1;

}

else

str.append("0");

str.append("0");

return str;

}

public:

zip_code(int barcode)

{

if(barcode<10000 || barcode>99999)

cout <<"Invalid Bar code passed to constructor." << endl;

else

zipcode = barcode;

}

zip_code(string barcode)

{

if(barcode.length()>27)

cout <<"Invalid Bar code passed to constructor." << endl;

else

{

int zipper = 0;

string str_local = barcode.substr(1,barcode.length()-2);

for(int i=0; i<str_local.length()-5; i+=5)

{

int local = 0;

local = 7*(str_local[i]-'0') +

       4*(str_local[i+1]-'0') +

       2*(str_local[i+2]-'0') +

       1*(str_local[i+3]-'0');

if(local == 11) local = 0;

       zipper = zipper*10 + local;

}

zipcode = zipper;

}

}

string getZipcode()

{

string str = "1";

int first = zipcode/10000;

int second = (zipcode - first*10000)/1000;

int third = (zipcode - first*10000-second*1000)/100;

int fourth = (zipcode - first*10000-second*1000-third*100)/10;

int fifith = (zipcode - first*10000-second*1000-third*100-fourth*10);

str.append(get_string(first));

str.append(get_string(second));

str.append(get_string(third));

str.append(get_string(fourth));

str.append(get_string(fifith));

str.append("1");

return str;

}

int get_zipCode()

{

return zipcode;

}

};

int main()

{

zip_code z1(123456);

zip_code z2(99504);

cout << z2.getZipcode() << endl;

system("pause");

return 0;

}

4 0
4 years ago
Over a TCP connection, suppose host A sends two segments to host B, host B sends an acknowledgement for each segment, the first
Margaret [11]

Answer:

a. Host A will retransmit neither segments

Explanation:

The options are:

a. Host A will retransmit neither segments

b. Host A will retransmit first segment

c. Host A will retransmit the second segment

d. Host A will retransmit both segments

The first acknowledgment is lost but the second acknowledgment arrives before the timer of the first segment expires, and hence the host A gets confirmation that Host B has received both the segments. And hence Host A will retransmit neither segments.

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3 years ago
The "c" key and the "e" key are struck by
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1 because when you type on the home row your left middle finger will hit both of those letters.
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She should report it to the superviser
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