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3 years ago

15

The pie store is having a 20\%20% off sale on all of its pies. If the pie you want regularly costs \$18$18, how much would you s

ave with the discount? \$

1 answer:

Keith_Richards [23]3 years ago

5 0

Answer:

$3.6

Step-by-step explanation:

We are told that the pie store is having a 20% off sale on all of its pies. The pie you want regularly costs $18.

To find the amount saved with the discount let us find 20% of 18.

$\text{The amount saved with discount}=\frac{20}{100}\times 18$

$\text{The amount saved with discount}=0.20\times 18$

$\text{The amount saved with discount}=3.6$

Therefore, the amount saved with the discount is $3.6.

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3 years ago

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2. Create an estimated probability distribution for the time teens spend texting.

Furkat [3]

Answer:

<u><em>Hours</em></u> 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0

<u><em>Frequency</em></u>* 0.2 0.09 0.25 0.18 0.11 0.07 0.05 0.02 0.01 0.02 0.01

Problem Statement:

The table shows the number of hours, to the nearest half hour per day, that teens spend texting according to a random sample of 870 teenagers aged 13–18 in a large urban city.

Hours 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0

Frequency 170 82 220 153 92 58 40 15 12 18 10

Step-By-Step Explanation:

As we need the estimated probability distribution for teens spending time texting, we will be needing the total sample size.

As given in the problem statement,

<em><u>Total Sample Size = 870</u></em>

To calculate estimated probability distribution, we will convert the frequency sample into estimated probability distribution, for that:

Estimated Probability Distribution (Frequency*)= $\frac{Frequency.Sample.Size.of.that.hour}{Total.Sample.Size}$

<u><em>For Example:</em></u>

Estimated probability distribution that teens spend 0 hours texting= $\frac{170}{870} =0.20$

Similarly

Estimated probability distribution that teens spend 0.5 hours= $\frac{82}{870} =0.09$

Using the same formula we get:

<em><u>Hours</u></em> 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0

<em><u>Frequency</u></em>* 0.2 0.09 0.25 0.18 0.11 0.07 0.05 0.02 0.01 0.02 0.01

(<em>Note: Frequency* is the estimated probability distribution)</em>

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3 years ago

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Please answer :( If it takes 1/3 cup of flour to make 1/4 of a cake, how many cups of flour are needed to make a whole cake?

denis-greek [22]

Answer:

1 $\frac{1}{3}$

Step-by-step explanation:

1/4cake=1/3cup

Now times both sides by 4

$\frac{1}{4}$ x $\frac{4}{1}$ =1 cake

$\frac{1}{3}$ x $\frac{4}{1}$ = $\frac{4}{3}$ which equals 1 $\frac{1}{3}$

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3 years ago

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Which point on the graph of g(x)=(1/5)^x? HELPP

Cloud [144]

Answer:

(-1,5) and $(3, \frac{1}{125})$ are points on the graph

Step-by-step explanation:

Given

$g(x) = \frac{1}{5}^x$

Required

Determine which point in on the graph

To get which of point A to D is on the graph, we have to plug in their values in the given expression using the format; (x,g(x))

A. (-1,5)

x = -1

Substitute -1 for x in $g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-1}$

Convert to index form

$g(x) = 1/(\frac{1}{5})$

Change / to *

$g(x) = 1*(\frac{5}{1})$

$g(x) = 5$

This satisfies (-1,5)

<em>Hence, (-1,5) is on the graph</em>

<em></em>

B. (1,0)

x = 1

Substitute 1 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^1$

$g(x) = \frac{1}{5}$

<em>(1,0) is not on the graph because g(x) is not equal to 0</em>

C. $(3, \frac{1}{125})$

x = 3

Substitute 3 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^3$

Apply law of indices

$g(x) = \frac{1}{5} * \frac{1}{5} * \frac{1}{5}$

$g(x) = \frac{1}{125}$

This satisfies $(3, \frac{1}{125})$

<em>Hence, </em> $(3, \frac{1}{125})$ <em> is on the graph</em>

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D. $(-2, \frac{1}{25})$

x = -2

Substitute -2 for x

$g(x) = \frac{1}{5}^x$

$g(x) = \frac{1}{5}^{-2}$

Convert to index form

$g(x) = 1/(\frac{1}{5}^2)$

$g(x) = 1/(\frac{1}{5}*\frac{1}{5})$

$g(x) = 1/(\frac{1}{25})$

Change / to *

$g(x) = 1*(\frac{25}{1})$

$g(x) = 25$

This does not satisfy $(-2, \frac{1}{25})$

<em>Hence, </em> $(-2, \frac{1}{25})$ <em> is not on the graph</em>

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4 years ago

there are 7 yellow marbles and 10 orange marbles in a bag you randomly choose one of the marbles what is the possibilty of choos

densk [106]

Answer:

probability; ( of choosing a yellow marble)

7 yellow marbles + 10 orange marbles = 17 in total

if the no of yellow marbles is 7 therefore = ⁷/10

so that is the probability ⁷/10

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3 years ago

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