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2 years ago

Find the measure of this angle m 1 = 123 m 8

Mathematics

1 answer:

Anit [1.1K]2 years ago

6 0

If it is parallel lines cut by a transversal then they are probably equal. Alternate exterior.

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What is the domain of g

olga nikolaevna [1]

Answer:

Step-by-step explanation:

The domain of g(x) is the set of all real numbers. Meaning that all the numbers between the min and max of g would be -7 ≤ x ≤ 7.

6 0

1 year ago

Two numbers that round to 300 when rounded to the nearest hundred

sashaice [31]

Answer:

335 and 289

Step-by-step explanation:

335 is rounded to 300 and 289 is rounded to 300

8 0

2 years ago

the length of a rectangle is 3 feet more than twice the width. if the width is increased by four feet the perimeter of the new r

densk [106]

Answer:

The area of the original rectangle = 189 sq ft.

Step-by-step explanation:

Let, the width of the rectangle = m feet

So, the length of the rectangle = (2 m + 3) ft

Now, new width w' = (m + 4)

Perimeter of new rectangle (P') = 68 ft

Perimeter of a rectangle = 2 (LENGTH + WIDTH)

⇒68 ft = 2( L + W')

or, 68 ft = 2 [( 2m + 3) + (m + 4)]

or, 2 (3m + 7) = 68

or, 3m + 7 = 68/2 = 34

⇒ 3m = 34 - 7 = 27

⇒ m = 27/3 = 9

or, m = 9 ft

Hence, the original width of the rectangle = 9 ft

Original Length of the rectangle = 2m + 3 = 2(9) + 3 = 21 ft

Now, Area of the Rectangle = LENGTH X WIDTH

= 21 ft x 9 ft = 189 sq ft

Hence,the area of the original rectangle = 189 sq ft.

5 0

3 years ago

Does this graph represent a function?Why or why not?

cestrela7 [59]

No, it does not have a straight line. (A)

4 0

3 years ago

Read 2 more answers

An 8-sided die is formed when two square pyramids are attached by their bases. The perimeter of the base shape is 6 centimeters.

bogdanovich [222]

1. Check the picture attached. Consider the half of the 8-sided die, that is the pyramid ABCDE:

2. The perimeter of the base is 6, so each side of the base is 6/4=3/2

3. The distance between the tallest points is 2 cm, si the height of Pyramid ABCDE is 1 cm.

4. Consider the right triangle EOM in the figure:

EO=1, OM= 3/4 (it is half of AB=3/2) and EM is the hypothenuse, so by the pythagorean theorem length of EM is $\sqrt{1+ ( \frac{3}{4} )^{2} }= \sqrt{1+ \frac{9}{16} }= \sqrt{ \frac{25}{16} }= \frac{5}{4}$ (cm)

5. So side EBC has area
$\frac{1}{2}BC*EM= \frac{1}{2}* \frac{3}{2}* \frac{5}{4}= \frac{15}{16}$

6. The total area is 8*Area(EBC)= $8* \frac{15}{16}= \frac{15}{2}=7.5 ( cm^{2} )$

6 0

3 years ago

Read 2 more answers