Since 30 lights are 40% of them:
30*2= 60
Since 2*40= 80
We still need the 20 percent.
Half of 40= 20.
30/2= 15
So, 15+60= 75
75 is the number of lights on the tree.
I hope this helps!
~cupcake
Perimeter of the quadrilateral = 48 cm
Solution:
The dimensions of the quadrilateral are 2x, 2x – 1, x – 3 and 3x.
The dimensions of the triangle are x + 3, 5 and x + 3.
<em>Perimeter of the polygon = Sum of the sides of the polygon</em>
The perimeter of the quadrilateral = 2 × Perimeter of the triangle
2x + 2x – 1 + x – 3 + 3x = 2 × (x + 3 + 5 + x + 3)
8x – 4 = 2 × (2x + 11)
8x – 4 = 4x + 22
Add 4 on both sides of the equation.
8x = 4x + 26
Subtract 4x on both sides of the equation.
4x = 26
Divide by 4 on both sides of the equation.
x = 6.5
Perimeter of the quadrilateral = 2 × (x + 3 + 5 + x + 3)
Perimeter of the quadrilateral = 2 × (6.5 + 3 + 5 + 6.5 + 3)
= 2 × (9.5 + 5 + 9.5)
= 2 × 24
= 48
Perimeter of the quadrilateral = 48 cm
Answer:
-22
Step-by-step explanation:
Plug in 5 for x.
y = -3(5) - 7
y = -15 - 7
y = -22
Answer:
2.Janice should know the area of her apartment that requires painting. This should be followed by calculating the area that 1 gallon of the paint can completely paint.Dividing the total area of the apartment to be painted with the area painted by a single gallon can will determined the number of gallon cans to buy for the apartment painting.
3. The approximate distance covered by 20 blocks is 1 mile.This is an example of Manhattan.A city planner can use this estimate to know the distance of a single city block by dividing 1 mile with 20 blocks.She can use 1 mile.
Answer: 60 trees
Explanation:
Even if there are trees planted per acre, the decrease of yield of each tree is significant enough to make it less worthwhile to have more trees than less.
In other words, when she plants 60 trees per acre, she gets 2700 bushels of fruit per acre, because 45 bushels per tree = 45 • 60 = 2700. If you plant another tree, you get the equation 41 • 61 = 2501 because there are 4 less bushels per tree. 2501 < 2700 so 60 per acre would maximize the harvest.
