Answer:
c) slope: -7 ; y-intercept: 2
Step-by-step explanation:
Note the slope intercept form:
y = mx + b
y = (x , y)
m = slope
x = (x , y)
b = y-intercept
Note in this case:
y = (-7)x + 2
y = y
m = -7
x = x
b = 2
c) slope: -7 ; y-intercept: 2 is your answer.
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Answer:
This is very detailed as I wish to make some principles about fractions clear.
3
5
12
Explanation:
This question boils down to
3
2
3
−
1
4
A fractions structure is that of:
count
size indicator of what you are counting
→
numerator
denominator
You can not directly add or subtract the counts (numerators) unless the size indicators (denominators) are the same.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Consider
3
2
3
Write as
3
+
2
3
Multiply by 1 and you do not change the value. However, 1 comes in many forms so you can change the way something looks without changing its true value
[
3
×
1
]
+
2
3
[
3
×
3
3
]
+
2
3
9
3
+
2
3
=
11
3
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Putting it all together
3
2
3
−
1
4
→
11
3
−
1
4
But the size indicators are not the same. I chose to make them become 12
11
3
−
1
4
→
[
11
3
×
1
]
−
[
1
4
×
1
]
→
[
11
3
×
4
4
]
−
[
1
4
×
3
3
]
→
44
12
−
3
12
Now we may subtract the counts
→
44
−
3
12
=
41
12
But this is the same as
12
12
+
12
12
+
12
12
+
5
12
=
1
2
+
2
1
2
+
2
1
2
+
5
12
=
3
5
12
Step-by-step explanation:
Answer: x=15
Step-by-step explanation: Since 3x+5 is equal to 50, you can write 3x+5=50, and 3x=45, x=15.
I think it’s d I’m not sure though
Answer: The numbers are: " 21 " and " 105 " .
___________________________________________________
Explanation:
___________________________________________________
Let "x" be the "one positive number:
Let "y" be the "[an]othyer number".
x = 1/5 (y)
___________________________________________________
Given that the difference of the two number is "84" ; and that "x" is (1/5) of "y" ; we determine that "x" is smaller than "y".
So, y − x = 84 .
Add "x" to each side of this equation; to solve for "y" in terms of "x" ;
y − x + x = 84 + x ;
y = 84 + x ;
___________________________________________________
So, we have:
x = (1/5) y ;
and: y = 84 + x ;
Substitute "(1/5)y" for "x" ; in "y = 84 + x " ; to solve for "y" ;
y = 84 + [ (1/5)y ]
Subtract " [ (1/5)y ] " from EACH SIDE of the equation ;
y − [ (1/5)y ] = 84 + [ (1/5)y ] − [ (1/5)y ] ;
to get:
[ (4/5)y ] = 84 ;
↔ (4y) / 5 = 84 ;
→ 4y = 5 * 84 ;
Divide EACH SIDE of the equation by "4" ;
to isolate "y" on one side of the equation; and to solve for "y" ;
4y / 4 = (5 * 84) / 4 ;
y = 5 * (84/4) = 5 * 21 = 105 .
y = 105 .
___________________________________________________
Now, plug "105" for "y" into:
___________________________________________________
Either:
___________________________________________________
x = (1/5) y ;
OR:
y = 84 + x ;
___________________________________________________
to solve for "x" ;
___________________________________________________
Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
___________________________________________________
Start with:
x = (1/5)y
→ (1/5)*(105) = 105 / 5 = 21 ; x = 21 ;
___________________________________________________
So, x = 21; y = 105 .
___________________________________________________
Now, let us see if this values hold true in the other equation:
___________________________________________________
y = 84 + x ;
105 = ? 84 + 21 ?
105 = ? 105 ? Yes!
___________________________________________________
The numbers are: " 21 " and "105 " .
___________________________________________________
