Answer:
I have made it in above figure
Answer:
1/6, 1/6, 630
Step-by-step explanation:
1/6*n-7≤98
1/6*n≤98+7
1/6*n≤105
n≤105*6
n≤630
y=kx+b
for (7,-8): -8=7k+b. (function 1)
for (-4,6): 6=-4k+b (function 2)
Use function 2 - function 1
we get: 14=-11k
k=-14/11------>slope is -14/11
Now we know that first two options are wrong since they have the wrong slope for the function.
Plus -14/11 back to function 1/ or 2. Both are correct and can give you the answer. In this case I would plug it back to function 2.
6=14*4/11+b
b=66/11-56/11
b=10/11
We get y=-14/11x+10/11
subtract both side by 6.
y-6=-14/11x+10/11-66/11
y-6=-14/11x-56/11
y-6=-14/11(x+4)
So C is correct
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
C. 3.50
Step-by-step explanation:
He bought a lunch two times, so $1.75*2 = 3.50.
