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3 years ago

What is the ratio of 6 nickles to 3 dollars

Mathematics

2 answers:

sashaice [31]3 years ago

7 0

so quarters to nickels would be 4:20. simplified is 1:5

masya89 [10]3 years ago

4 0

There are a few ways to represent ratio. Since 6 nickels comes first in the statement, it will come first in the ratio, and 3 dollars will come second since it comes second in the statement.

You can express ration with a / sign, a : sign, and the word to. So, your ratio would look like this:

6/3

6:3

6 to 3

Hope this helps!

You might be interested in

Select all angles that MUST be supplementary to 9

erastova [34]

Answer:

Angles supplementary to angle 9 = Angle 10, 7, 5, 1, 4, 3, 15, 12, 24, 22, 20, 19, and angle 16.

Step-by-step explanation:

Use the vertical, and corresponding angles theorem to find congruent angles.

Look for linear pairs (adjacent(next to each other, or share a side) angles that make 180° or a straight angle) from the corresponding angles.

Something is supplementary if it adds to 180 degrees.

The vertical angles theorem states that pairs of opposite angles made by interesecting lines are congruent.

The corresponding angles theorem states that corresponding or angles relative to the same position are congruent if the transversal crosses at least 2 parallel lines.

6 0

3 years ago

The sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number.

Tema [17]

Answer:

2 $\frac{1}{16}$

Step-by-step explanation:

The question state that; the sum of a number, 1/6 of that number, 2 1/2 of that number, and 7 is 12 1/2. Find the number.

First, we need to interpret and represent this statement mathematically

Let n be the number.

The sum means 'addition'

1/6 of that number is 1/6 of n = 1/6 × n = $\frac{n}{6}$

2 1/2 of that number is 2 1/2 of n = 2 1/2 × n = 5/2 × n = $\frac{5n}{2}$

So the question says that, when we add; $\frac{n}{6}$ , $\frac{5n}{2}$ and 7 all together, the value is 12 1/2

That is;

$\frac{n}{6}$ + $\frac{5n}{2}$ + 7 = 12 1/2

$\frac{n}{6}$ + $\frac{5n}{2}$ + 7 = $\frac{25}{2}$ ( changing 12 1/2 to improper fraction will give $\frac{25}{2}$ )

So we can now go ahead and solve for n

$\frac{n}{6}$ + $\frac{5n}{2}$ + 7 = $\frac{25}{2}$

subtract 7 from both-side of the equation

$\frac{n}{6}$ + $\frac{5n}{2}$ = $\frac{25}{2}$ - 7

$\frac{n + 15n}{6}$ = $\frac{25 -14}{2}$

$\frac{16n}{6}$ = $\frac{11}{2}$

$\frac{16n}{6}$ can be reduced to give us $\frac{8n}{3}$

$\frac{8n}{3}$ = $\frac{11}{2}$

Cross multiply

8n × 2 = 11× 3

16n = 33

Divide both-side of the equation by 16

$\frac{16n}{16}$ = $\frac{33}{16}$

(On the left-hand side of the equation, 16 will cancel-out 16 leaving us with just, while on the right-hand side of the equation 33 will be divided by 16)

n = $\frac{33}{16}$ = $2\frac{1}{16}$