Answer:
25 and 21 hours respectively
Step-by-step explanation:
Let the number of hours worked by each welder be x and y respectively.
They worked a total of 46 hours. This means :
x + y = 46 hours.......(I)
Now, given their hourly charges, since we have the total amount of money realized, we can make an equation out of it. This means:
34x + 39y = 1669........(ii)
We then solve both simultaneously. From I, x = 46 -y
We can substitute this into ii
34(46 -y) + 39y = 1669
1564 -34y + 39y = 1669
5y = 1669 - 1564
5y = 105
y = 105/5 = 21
x = 46 - y
x = 46 - 21 = 25 hours
The numbers of hours worked by the welders are 25 and 21 respectively
60 ≥ 35 + 5t
<u>-35 </u><u> </u><u>-35 </u>
<u>25</u> ≥ <u>5t</u>
5 5
t≤5
his mistake was that he used ≤ for at least instead of using ≥. so at end, when I solved, I saw that Sven should spend 5 minutes or less on each scale.
We're looking for the two values being subtracted here. One of these values is easy to find:
<span>g(1) = ∫f(t)dt = 0</span><span>
since taking the integral over an interval of length 0 is 0.
The other value we find by taking a Left Riemann Sum, which means that we divide the interval [1,15] into the intervals listed above and find the area of rectangles over those regions:
</span><span>Each integral breaks down like so:
(3-1)*f(1)=4
(6-3)*f(3)=9
(10-6)*f(6)=16
(15-10)*f(10)=10.
So, the sum of all these integrals is 39, which means g(15)=39.
Then, g(15)-g(1)=39-0=39.
</span>
I hope my answer has come to your help. God bless and have a nice day ahead!
The factor of mn+5m-3n-15 is 6m-4n-15.
