Answer:
.6
Step-by-step explanation:
I'm pretty sure the attachment down there can answer ur question! :D
Answer:
The correct option is (c).
Step-by-step explanation:
The complete question is:
The data for the student enrollment at a college in Southern California is:
Traditional Accelerated Total
Math-pathway Math-pathway
Female 1244 116 1360
Male 1054 54 1108
Total 2298 170 2468
We want to determine if the probability that a student enrolled in an accelerated math pathway is independent of whether the student is female. Which of the following pairs of probabilities is not a useful comparison?
a. 1360/2468 and 116/170
b. 170/2468 and 116/1360
c. 1360/2468 and 170/2468
Solution:
If two events <em>A</em> and <em>B</em> are independent then:

In this case we need to determine whether a student enrolled in an accelerated math pathway is independent of the student being a female.
Consider the following probabilities:

If the two events are independent then:
P (F|A) = P(F)
&
P (A|F) = P (A)
But what would not be a valid comparison is:
P (A) = P(F)
Thus, the correct option is (c).
Answer:
a) The variable, M represents the amount of fish Ms. Montesinos has
b) The set equation is 11 + 2 = 3 × M - 2
c) 5
Step-by-step explanation:
The given parameters are;
The number of fishes in Ms. Cruz's tank = 11 fishes
The number of fishes Ms, Cruz has after buying two more fishes = 3 × The amount of fish Ms. Montesinos has - 2 fishes
a) Let the variable, M represent the amount of fish Ms. Montesinos has
b) The set up equation is as follows;
11 + 2 = 3 × M - 2
c) From the equation, 11 + 2 = 3 × M - 2, we have;
13 = 3·M - 2
3·M = 13 + 2 = 15
3·M = 15
M = 15/3 = 5
M = 5
The number of fishes Ms. Montesinos has is 17 fishes
Solve by elimination.
The goal is to cancel out one of the variables in order to easily solve for the other variable.
Do this by changing the equations so that the coefficients of either x or y add up to 0.
Notice the coefficients of y are 3 and 3, if we make one of them negative then they add up to 0. 3+ (-3) = 0
Multiply 2nd equation by -1.
6x +3y = 9
-2x -3y = -1
__________
4x +0y = 8
Solve for x
4x = 8
x = 8/4 = 2
Plug x=2 back into one of original equations to find y.
---> 2(2) + 3y = 1
---> 4 + 3y = 1
---> 3y = -3
---> y = -1
Therefore solution is (2,-1)