P/9 = 90
Multiply 9 to 90 to isolate the variable.
P = 9 x 90
P = 810
Yes
The rule to check if a triplet of numbers can represent the sides of a triangle is the following: the sum of the length of two sides must exceed the third one.
This happens for all possible couples in your case:



if there were 100 questions then 76 were correct, and 24 incorrect, you can simplify and rearrange the fraction depending on how many questions there were,
Answer:
XZ = 26.7
ZY = 11.7
Area = 140.4 sq inches
Step-by-step explanation:
m∠Z = 180-(26+90) = 64°
to get XZ you can use the law of sines:
sin 90°/XZ = sin 64°/24
1/XZ = sin(64°)
cross-multiply to get:
XZ·sin(64°) = 24
XZ = 24/sin(64°)
XZ = 26.7
to get ZY you can use the law of sines again:
sin 64°/24 = sin 26°/ZY
cross-multiply to get:
ZY·sin(64°) = 24·sin(26°)
ZY = 24·sin(26°) ÷ sin(64°)
ZY = 11.7
Area = 1/2(11.7)(24)
= 12(11.7)
= 140.4 sq inches
D. x = 3 because 3+3 is 6 and that is over 2*3^2 which is 2*9 which means it is 6/18 then you divide both the numerator and denominator by 6 and that =1/3.