If you wanted the laser to refract less as it exits the prism, you should increase the wavelength of the light.
<h3>What is
refraction?</h3>
Refraction can be defined as a phenomenon which describes a change (bend) in the path taken by light when it's at surfaces between different transparent materials.
According to the model of light wave, the refraction of light is inversely proportional to its wave. Thus, you should increase the wavelength of light, if you want the laser to refract less as it exits the prism.
Read more on refraction here: brainly.com/question/15838784
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So I am assuming that by "the following," you mean in general terms.
The shortest wavelength of the spectrum is the Gamma Ray waves, they are 400nm and are the most deadly, because of how often and frequent they are able to vibrate. Shorter the wavelength the more active.
So the list from "shortest," to "longest," is,
Gamma Ray, X-Ray, Ultraviolet, Visible, Infrared, Microwave, and Radio wavelengths.
In the spectrum, Radio has the longest and furthest traveling waves. This means that they are not harmful and that they can travel extreme distances.
Hope this helps!
Not possible. The air is actually able to travel sound throughout itself without any difficulties. I believe, air actually brings sound closer to the people farther away ; It really helps to stretch sound.
Answer:
- The x-component of the velocity of the third particle is
![- 1.50 \ 10 ^{7} \frac{m}{s}](https://tex.z-dn.net/?f=-%201.50%20%5C%2010%20%5E%7B7%7D%20%5Cfrac%7Bm%7D%7Bs%7D)
- The y-component of the velocity of the third particle is
![- 1.34 \ 10 ^{-20} \frac{\ m}{s}](https://tex.z-dn.net/?f=-%201.34%20%5C%2010%20%5E%7B-20%7D%20%5Cfrac%7B%5C%20m%7D%7Bs%7D)
- The increase in kinetic energy is
![E= 6.1586 \ 10 ^ {-13} Joules](https://tex.z-dn.net/?f=E%3D%206.1586%20%5C%2010%20%5E%20%7B-13%7D%20Joules%20)
Explanation:
We can take conservation of linear momentum to find the velocities:
The initial momentum of the nucleus will be:
![\vec{P}_0=0](https://tex.z-dn.net/?f=%5Cvec%7BP%7D_0%3D0)
as is at rest.
After the decay, the first particle has a momentum
![\vec{P}_1 = m_1 \ \vec{V}_1 = 5.04 \ 10^{-27} kg \ * ( 0 \ , \ 6.00 \ 10 ^{6} \frac{m}{s})](https://tex.z-dn.net/?f=%5Cvec%7BP%7D_1%20%3D%20m_1%20%5C%20%5Cvec%7BV%7D_1%20%3D%205.04%20%5C%2010%5E%7B-27%7D%20kg%20%20%5C%20%2A%20%28%200%20%20%5C%20%2C%20%5C%206.00%20%5C%2010%20%5E%7B6%7D%20%5Cfrac%7Bm%7D%7Bs%7D%29)
![\vec{P}_1 = ( 0 \ , \ 3.024 \ 10 ^{-20} \frac{kg \ m}{s})](https://tex.z-dn.net/?f=%5Cvec%7BP%7D_1%20%3D%20%28%200%20%20%5C%20%2C%20%5C%203.024%20%5C%2010%20%5E%7B-20%7D%20%5Cfrac%7Bkg%20%5C%20m%7D%7Bs%7D%29)
the second one has a momentum
![\vec{P}_2 = m_2 \ \vec{V}_2 = 8.50 \ 10^{-27} kg \ * ( 4.00 \ 10 ^{6} \frac{m}{s} \ , \ 0)](https://tex.z-dn.net/?f=%5Cvec%7BP%7D_2%20%3D%20m_2%20%5C%20%5Cvec%7BV%7D_2%20%3D%208.50%20%5C%2010%5E%7B-27%7D%20kg%20%20%5C%20%2A%20%28%20%204.00%20%5C%2010%20%5E%7B6%7D%20%5Cfrac%7Bm%7D%7Bs%7D%20%5C%20%2C%20%5C%200%29)
![\vec{P}_2 = ( 3.4 \ 10 ^{-20} \frac{kg \ m}{s} \ , \ 0)](https://tex.z-dn.net/?f=%5Cvec%7BP%7D_2%20%3D%20%28%20%203.4%20%5C%2010%20%5E%7B-20%7D%20%5Cfrac%7Bkg%20%5C%20m%7D%7Bs%7D%20%5C%20%2C%20%5C%200%29)
By conservation of linear momentum we have:
![\vec{P}_0= \vec{P}_1 + \vec{P}_2 + \vec{P}_3](https://tex.z-dn.net/?f=%5Cvec%7BP%7D_0%3D%20%5Cvec%7BP%7D_1%20%2B%20%20%5Cvec%7BP%7D_2%20%2B%20%5Cvec%7BP%7D_3)
![\vec{P}_3= -\vec{P}_1 - \vec{P}_2](https://tex.z-dn.net/?f=%5Cvec%7BP%7D_3%3D%20-%5Cvec%7BP%7D_1%20-%20%5Cvec%7BP%7D_2%20)
![\vec{P}_3= ( - 3.4 \ 10 ^{-20} \frac{kg \ m}{s} \ , \ - 3.024 \ 10 ^{-20} \frac{kg \ m}{s})](https://tex.z-dn.net/?f=%5Cvec%7BP%7D_3%3D%20%28%20-%203.4%20%5C%2010%20%5E%7B-20%7D%20%5Cfrac%7Bkg%20%5C%20m%7D%7Bs%7D%20%5C%20%2C%20%5C%20-%203.024%20%5C%2010%20%5E%7B-20%7D%20%5Cfrac%7Bkg%20%5C%20m%7D%7Bs%7D%29%20)
for the third particle, we know that mass is conserved:
![m_0 = m_1 + m_2 + m_3](https://tex.z-dn.net/?f=m_0%20%3D%20m_1%20%2B%20m_2%20%2B%20m_3)
![m_3 = m_0 - m_1 - m_2](https://tex.z-dn.net/?f=m_3%20%3D%20m_0%20-%20m_1%20-%20m_2)
![m_3 = 1.58 \ 10^{-26} kg - 5.04 \ 10^{-27} kg - 8.50 \ 10^{-27} kg](https://tex.z-dn.net/?f=m_3%20%3D%201.58%20%5C%2010%5E%7B-26%7D%20kg%20-%205.04%20%5C%2010%5E%7B-27%7D%20kg%20-%208.50%20%5C%2010%5E%7B-27%7D%20kg)
![m_3 = 2.26 \ 10^{-27} kg](https://tex.z-dn.net/?f=m_3%20%3D%202.26%20%5C%2010%5E%7B-27%7D%20kg)
The velocity will be:
![\vec{v}_3 = \frac{1}{m_3} \vec{P}_3](https://tex.z-dn.net/?f=%5Cvec%7Bv%7D_3%20%3D%20%5Cfrac%7B1%7D%7Bm_3%7D%20%5Cvec%7BP%7D_3)
The kinetic energy is given by
![E= \frac{1}{2} m_1 v_1^2 + m_2 v_2^2 + m_3 v_3^2](https://tex.z-dn.net/?f=E%3D%20%5Cfrac%7B1%7D%7B2%7D%20m_1%20v_1%5E2%20%2B%20m_2%20v_2%5E2%20%2B%20m_3%20v_3%5E2)
![E= \frac{1}{2} 5.04 \ 10^{-27} kg \ (6.00 \ 10 ^{6} \frac{m}{s}) ^2 \\ \\ + \frac{1}{2} 8.50 \ 10^{-27} kg \ (4.00 \ 10 ^{6} \frac{m}{s}) ^2 \\ \\ + \frac{1}{2} 2.26 \ 10^{-27} kg \ ((- 1.50 \ 10 ^{7} \frac{m}{s}) ^2+(- 1.34 \ 10 ^{-7} \frac{\ m}{s})^2)](https://tex.z-dn.net/?f=E%3D%20%5Cfrac%7B1%7D%7B2%7D%205.04%20%5C%2010%5E%7B-27%7D%20kg%20%5C%20%286.00%20%5C%2010%20%5E%7B6%7D%20%5Cfrac%7Bm%7D%7Bs%7D%29%20%5E2%20%5C%5C%20%5C%5C%20%2B%20%5Cfrac%7B1%7D%7B2%7D%208.50%20%5C%2010%5E%7B-27%7D%20kg%20%5C%20%284.00%20%5C%2010%20%5E%7B6%7D%20%5Cfrac%7Bm%7D%7Bs%7D%29%20%5E2%20%5C%5C%20%5C%5C%20%2B%20%5Cfrac%7B1%7D%7B2%7D%202.26%20%5C%2010%5E%7B-27%7D%20kg%20%5C%20%28%28-%201.50%20%5C%2010%20%5E%7B7%7D%20%5Cfrac%7Bm%7D%7Bs%7D%29%20%5E2%2B%28-%201.34%20%5C%2010%20%5E%7B-7%7D%20%5Cfrac%7B%5C%20m%7D%7Bs%7D%29%5E2%29)
![E= 9.072 \ 10 ^ {-14} Joules + 6.8 \ 10 ^ {-14} Joules + 2.5425 \ 10^{-13} Joules + 2.029 \ 10^{-13} Joules](https://tex.z-dn.net/?f=E%3D%209.072%20%5C%2010%20%5E%20%7B-14%7D%20Joules%20%2B%206.8%20%5C%2010%20%5E%20%7B-14%7D%20Joules%20%2B%202.5425%20%5C%2010%5E%7B-13%7D%20Joules%20%2B%202.029%20%5C%2010%5E%7B-13%7D%20Joules)
![E= 6.1586 \ 10 ^ {-13} Joules](https://tex.z-dn.net/?f=E%3D%206.1586%20%5C%2010%20%5E%20%7B-13%7D%20Joules%20)
And, as the initial kinetic energy is zero, this must be the increase in energy.
Answer:Both are correct
Explanation:
Both are correct because
Mechanical efficiency is the dimensionless term which is the ratio of brake horsepower to the Indicated horse Power
Where brake power is the Power obtained at the crankshaft and
Indicated horsepower is the power obtained in the combustion chamber and this power is the loss in the form of friction.
Volumetric efficiency is the ratio of actual fuel intake to the maximum air fuel that could be taken.