<h2>
Its velocity when it crosses the finish line is 119.40 m/s</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
Initial velocity, u = 0 m/s
Acceleration, a = ?
Time, t = 6.70 s
Displacement, s = 1/4 mi = 0.25 mi = 400 m
Substituting
s = ut + 0.5 at²
400 = 0 x 6.70 + 0.5 x a x 6.70²
a = 17.82 m/s²
Now we have equation of motion v = u + at
Initial velocity, u = 0 m/s
Final velocity, v = ?
Time, t = 6.7 s
Acceleration, a = 17.82 m/s²
Substituting
v = u + at
v = 0 + 17.82 x 6.7
v = 119.40 m/s
Its velocity when it crosses the finish line is 119.40 m/s
Radiated away as electromagnetic radiation.
I think it would be at 3 or 6 but I would go with 3 not really sure tho
Explanation:
a. Average speed = distance / time
= 100 m / 70 s
= 1.43 m/s
b. Average displacement = displacement / time
= 0 m / 70 s
= 0 m/s
Distance is the length of the path traveled. Displacement is the difference between the final position and initial position.
