Answer:
The angle between the red and blue light is 1.7°.
Explanation:
Given that,
Wavelength of red = 656 nm
Wavelength of blue = 486 nm
Angle = 37°
Suppose we need to find the angle between the red and blue light as it leaves the prism
We need to calculate the angle for red wavelength
Using Snell's law,
Put the value into the formula
We need to calculate the angle for blue wavelength
Using Snell's law,
Put the value into the formula
We need to calculate the angle between the red and blue light
Using formula of angle
Put the value into the formula
Hence, The angle between the red and blue light is 1.7°.
+1
An electron has a negative charge so losing a charge of -1 from an uncharged, or neutral, atom will leave an ion with a positive charge.
Answer:
answer below
Explanation:
Displacement of the student is 739 m due North and it takes 162 s.
We need to find the student's average velocity. Using formula of velocity.
Velocity = displacement/time
v= 739/162
v= 4.56
Answer:
A) 21.2 kg.m/s at 39.5 degrees from the x-axis
Explanation:
Mass of the smaller piece = 200g = 200/1000 = 0.2 kg
Mass of the bigger piece = 300g = 300/1000 = 0.3 kg
Velocity of the small piece = 82 m/s
Velocity of the bigger piece = 45 m/s
Final momentum of smaller piece = 0.2 × 82 = 16.4 kg.m/s
Final momentum of bigger piece = 0.3 × 45 = 13.5 kg.m/s
since they acted at 90oc to each other (x and y axis) and also momentum is vector quantity; then we can use Pythagoras theorems
Resultant momentum² = 16.4² + 13.5² = 451.21
Resultant momentum = √451.21 = 21.2 kg.m/s at angle 39.5 degrees to the x-axis ( tan^-1 (13.5 / 16.4)
