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Alex787 [66]
3 years ago
11

Tìm chỉ số của A1 và A2

Physics
1 answer:
ziro4ka [17]3 years ago
6 0

Answer:

A1

Explanation:

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When solar flares increase solar wind from the corona what do they cause in earth's upper atmosphere?
Strike441 [17]

They cause magnetic storms. A magnetic storm is a fleeting disturbance of the Earth's magnetosphere. A magnetic storm is caused by a solar wind shock wave associated with solar coronal mass ejections, coronal holes, or solar flares. It typically strikes the Earth's magnetic field 24 to 36 hours after the event.

5 0
4 years ago
An electrical current flowing through a filament bulb causes it to get hot. Explain why this
sergij07 [2.7K]

Answer:

The reason the filament heats up is because it has a high resistance, which means that as electrons move through the filament, they lose a lot of energy.

First, what is current? Current is comprised of electrons moving through an electric field from a high electric potential to a lower potential. For the current to decrease then, something would need to happen to the electrons that go into the light bulb.  If 1 electron goes into the light bulb, then at the end of everything I need to still have 1 electron someplace. So how do electrons passing through the bulb make light?

Incandescent light bulbs have a small filament which when heated begins to glow and emit light.  The reason the filament heats up is because it has a high resistance, which means that as electrons move through the filament, they lose a lot of energy.  You can think of it as walking on a sidewalk compared to walking in waist deep water.  A wire is like a sidewalk. It has some resistance, but it is so tiny that it can generally be ignored which is why wires are useful in electronic circuits. The high resistance of the light bulb is like trying to walk through waist deep water.  Here energy is being taken from the electrons because of the interactions with the atoms in filament which causes those atoms to heat up, which in turn makes them emit light.

The light bulb is not doing anything to the electrons, so we expect then that any electrons going into the bulb should come out the other side. Since current is just flowing electrons, current stays the same.

Since current is the same on both sides, we know that the electrons are all moving together. Think of it like being in a big loop of people. Since everyone is in a big line you could imagine that you could only move as fast as the slowest person in the line. If everyone is on a big loop of sidewalk then everyone could run around in a circle. This is like having a large current in a loop of wire, or what we call a short. To put the equivalent of a lightbulb into our human circuit, imagine that one section of the sidewalk dips into a pool of water. Now everyone is stuck going as fast as the people trudging through the water. This is why current everywhere in a circuit is smaller when a resistor is introduced. As people trudge through the water they have to work hard to get through the water and they use energy.  In a circuit, this energy comes from the voltage source, like a battery.  The battery loses energy because it has to "pull" the electrons through the high resistance, and this is why the voltage drops across the light bulb

7 0
3 years ago
A purse at radius 2.30 m and a wallet at radius 3.45 m travel in uniform circular motion on the floor of a merry-go-round as the
ivolga24 [154]

Answer:

The acceleration of the wallet is 3\hat{i}+6\hat{j}

Explanation:

Given that,

Radius of purse r= 2.30 m

Radius of wallet r'= 3.45 m

Acceleration of the purse a=2\hat{i}+4.00\hat{j}

We need to calculate the acceleration of the wallet

Using formula of acceleration

a=r\omega^2

Both the purse and wallet have same angular velocity

\omega=\omega'

\sqrt{\dfrac{a}{r}}=\sqrt{\dfrac{a'}{r'}}

\dfrac{a}{r}=\dfrac{a'}{r'}

\dfrac{a'}{a}=\dfrac{r'}{r}

\dfrac{a'}{a}=\dfrac{3.45}{2.30}

\dfrac{a'}{a}=\dfrac{3}{2}

a'=\dfrac{3}{2}\times(2\hat{i}+4.00\hat{j})

a'=3\hat{i}+6\hat{j}

Hence, The acceleration of the wallet is 3\hat{i}+6\hat{j}

4 0
3 years ago
What is the magnitude of the initial velocity?
lesya692 [45]

Magnitude of initial velocity

<em>To calculate the </em><em>magnitude</em><em> of the </em><em>velocity</em><em> at any point in time, multiply the constant acceleration rate times the time difference and then add it to the </em><em>initial velocity.</em><em> As an example, if you dropped a rock off a cliff, its </em><em>velocity</em><em> increases by 32 feet per second, every second.</em>

<em />

<h2><em>Hope this helps you a lot ...</em></h2><h2><em>Good day :)</em></h2>

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