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Goryan [66]
3 years ago
8

If two figures have the same perimeter, they are congruent. True or false?

Mathematics
2 answers:
vaieri [72.5K]3 years ago
7 0
False.

Two figures may be different shape and have the same perimeter (a square and a circle, for example). If they are different shape, they will not be congruent.
AveGali [126]3 years ago
5 0
False, a trapezoid and a square can have the same perimeter but not be confruent<span />
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A student studying for a vocabulary test knows the meanings of 14 words from a list of 22 words. If the test contains 10 words f
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The sample space is 22 words and out of it, 14 words are known to have meanings for the student. In the problem, we use 10 C8 + 10 C9 + 10 C10 to associate at least 8 words. The complete formula is (10 C8 * (14/22)^8 * (8/22)^2 + 10 C9  (14/22)^9 * (8/22)^1 + 10 C 10 (14/22)^10 * (8/22)^)0) that is equal to 0.233
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3 years ago
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4. The population of Bay Village is 35,000 today. Every year the
frosja888 [35]

Answer:

Linear Model:   y(x)=35,000+750x

Step-by-step explanation:

In principle <em>Linear Models </em>are employed when we want to define a relationship between an independent and a dependent variable. <em>Linear Models</em> are also known as<em> Functions </em>, where one variable is expressed as a function of <em>at least one</em> other variable. The most common example would be a dependent variable y that is directly linked as a response to any changes of an independent variable x. The most common expression of such relationship would be y=ax where a is the relationship factor between y and x and is also known as the <em>slope </em>of the function (representing a rate of change of that function).

In this question we are told that the population of Bay Village today is 35,000. So we know this is our constant variable, lets call it  b.

Next we know that every year the population is increased by 750 people. So we know that our variable and thus our independent variable is every year which we shall call x and our fixed factor is the 750 increment which we will call a.  

From that we can conclude that:

<em>Year 1 Population: 35,000</em>

<em>Year 2 Population: 35,000 + 750 = 35,750</em>

<em>Year 3 Population: 35,750 + 750 = 36,500 </em>

And so on and so forth.<em> </em>

So we want to express the above as a Linear Model of the form:

<em> y = ax + b   </em>Eqn(1).

Thus from Eqn (1) and all information given (i.e. pluging in values) we finally obtain:

y(x)=35,000+750x

Which for every different value of  x (i.e. every year) we can obtain the new and increased population  y(x).

7 0
3 years ago
Please help asap!! 35 points!!!!!
shutvik [7]
I don't think it is linear b/c i don't think you can plug in the numbers and get it to work. This may not be right though b/c I did this in my head.
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3 years ago
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I need help NOW!!!!!!!!!!!
weqwewe [10]

Its just 30x60=1800...right?

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3 years ago
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