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SOVA2 [1]
3 years ago
5

Midwest Water Works estimates that its WACC is 10.45%. The company is considering the following capital budgeting projects.Assum

e that each of these projects is just as risky as the firm's existing assets and that the firm may accept all the projects or only some of them. Which set of projects should be accepted?Project Size Rate of Return A $1 million 12.0% B 2 million 11.5 C 2 million 11.2 D 2 million 11.0 E 1 million 10.7 F 1 million 10.3 G 1 million 10.2 Accept or Dont Accept A through G.
Mathematics
1 answer:
irinina [24]3 years ago
7 0

Answer:

Don't accept A-G

Accept only A-E

Step-by-step explanation:

The company would those projects with a return of return equal to or higher than its cost of capital of 10.45%

Project A with a 12% return is acceptable.

Project B with a 11.5% rate of return is also acceptable

Project C has a  rate of return of 11.2% , hence acceptable.

Project D has 11% rate of return and it is therefore acceptable.

Project E has 10.7% return rate and it is acceptable.

Project F has a lower rate of return of 10.3%, hence rejected, as well as projects G

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Two trains travel at right angles to each other after leaving the same train station at the same time. Two hours later they are
Alex787 [66]

Answer:

15 miles per hour is the speed of the slower train.

Step-by-step explanation:

As given in the figure attached,

Let the speed of train 1 is v and train 2 is u.

Therefore, distance traveled in 2 hours by train 1 will be = 2v miles

and distance traveled by train 2 will be = 2u miles

Now we can see in the figure a right angle triangle is formed by the two trains.

AB² + BC² = AC²

(2v)² + (2u)²= (65.30)²

4v² + 4u² = 4264.09

Now we divide this equation by 4

v² + u² = 1066.02

If speed of the slower train is v miles per hour then as per statement of the question.

u = v - 14

v = u + 14

By putting the value of v in the equation

(u + 14)² + u² = 1066

u² + 196 + 28u + u² = 1066

2u² + 28u + 196 = 1066

2u² + 28u + 196 - 1066 = 0

2u² + 28u - 870 = 0

By diving this equation by 2

u² + 14u - 435 = 0

u² + 29u - 15u - 435 = 0

u(u + 29) - 15(u + 29) = 0

(u + 29)(u - 15) = 0

u = -29, 15

Since speed can not be with negative notation so u = 15 miles per hour will be the speed.

Therefore, 15 miles per hour is the speed of the slower train.

5 0
3 years ago
Identify the number that does not belong with the other three. Explain your reasoning. 26.6 repeating 6, square root 48, negativ
noname [10]
The square root of 48 is the only irrational number in that group.
5 0
3 years ago
Read 2 more answers
Please help its from the lines and angles chapter
Murrr4er [49]

This is the answer of this question

4 0
3 years ago
For what values do maximum r-values occur on the graph the polar equation
blagie [28]

Answer:

We have the function:

r = -3 + 4*cos(θ)

And we want to find the value of θ where we have the maximum value of r.

For this, we can see that the cosine function has a positive coeficient, so when the cosine function has a maximum, also does the value of r.

We know that the meaximum value of the cosine is 1, and it happens when:

θ = 2n*pi, for any integer value of n.

Then the answer is  θ = 2n*pi, in this point we have:

r = -3 + 4*cos (2n*pi) = -3 + 4 = 1

The maximum value of r is 7

(while you may have a biger, in magnitude, value for r if you select the negative solutions for the cosine, you need to remember that the radius must be always a positive number)

5 0
3 years ago
Read 2 more answers
3/4 part of a rope is 150m. find the length of 7/10 part of the rope
a_sh-v [17]

Answer:

140m

Step-by-step explanation:

3/4 = .75

x/.7 = 150/.75

multiply both sides by .7

x = 150/.75 * .7

x = 140m

6 0
2 years ago
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