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3 years ago

2t - 5 = -10 what is t

Mathematics

2 answers:

jenyasd209 [6]3 years ago

6 0

The answer is -.2.5 hope that help

jonny [76]3 years ago

6 0

2t-5=-10
2t=-5 <---add 5 to each side
t=-2.5 <--- divide by 2
t=-2.5 FINAL ANSWER

Hope this helps!

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3 years ago

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2) Line segment MK has endpoints at (2, 3) and (5, ?4). Segment M'K' is the reflection of MK over the y-axis. Which statement de

Marianna [84]

Answer:

Option C -M'K' is the same length as MK

Step-by-step explanation:

Given : Line segment MK has endpoints at (2, 3) and (5,4)

M'K' is the reflection of MK over the y-axis

By definition of reflection: reflection of point (x,y) across the the y-axis is the point (-x,y)

which implies M'K' has end points (-2,3) and (-5,4)

Now, we find the length of MK

let $(x_1,y_1)=(2,3)\\\\(x_2,y_2)=(5,4)$

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

⇒ $d=\sqrt{(2-5)^2+(4-3)^2}$

⇒ $d=\sqrt{9+1}$

⇒ $d=\sqrt{10}$ ....(1)

Now, we find the length of M'K'

let $(x_1^{'},y_1^{'})=(-2,3)\\\\(x_2^{'},y_2^{'})=(-5,4)$

$d^{'}=\sqrt{(x_2^{'}-x_1^{'})^2+(y_2^{'}-y_1^{'})^2}$

⇒ $d^{'}=\sqrt{(-2+5)^2+(3-4)^2}$

⇒ $d^{'}=\sqrt{9+1}$

⇒ $d^{'}=\sqrt{10}$ .....(2)

from (1) and (2) we simply show that the length of MK and M'K' is equal

we can also refer the figure attached for reflection of MK and M'K'

therefore, Option C is correct

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3 years ago

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Answer:

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ax²+bx+c=0 (quadratic equation)

x= -b ± √b² - 4ac

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2 years ago

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gayaneshka [121]

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3 years ago

If p and q vary inversely and pp is 23 when q is 6, determine q when p is equal to 69.

Lina20 [59]

Answer:

Answer is q = 2

Step-by-step explanation:

First make the equation with a constant so p=k/q

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Then you have 23=k/6 and to find k multiply both sides to get k=138

next substitute p as 69=138/q then multiply q on both sides to get 69xq=138 and then divide 69 to 138 go get q which is 2

Like if it helped!

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1 year ago