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3 years ago

I need help with this one

Mathematics

2 answers:

Anika [276]3 years ago

7 0

Answer:

Step-by-step explanation:

if you look closely, you can see that the side of it goes up 2, then 2, then 1.

baherus [9]3 years ago

4 0

Answer:

The one on the right

Step-by-step explanation:

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What is the area of the resulting two dimensional cross section?

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A....if its wrong im sorry but i believe its a because you will do 4x4 and will get the sum of 16ft square

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3 years ago

If 180°<θ<270°, and sin⁡θ=−3/4, what is the value of sin(−θ)?

Oxana [17]

Answer:

$sin(-\theta)=\frac{3}{4}$

Step-by-step explanation:

Given:

180°<θ<270° and $sin(\theta)=-\frac{3}{4}$

We know for any angle $\theta$ ,

$sin(-\theta)=-sin(\theta)$

∴ $sin(-\theta)=-(-\frac{3}{4})=\frac{3}{4}$

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4 years ago

A central angle θ in a circle of radius 4 m is subtended by an arc of length 5 m. find the measure of θ in degrees. (round your

koban [17]

Answer:

$\theta=71.6\°$

Step-by-step explanation:

step 1

Find the circumference of the circle

The circumference is equal to

$C=2\pi r$

we have

$r=4\ m$

substitute the values

$C=2\pi (4)=8 \pi\ m$

step 2

Remember that

360 degrees subtends the arc of length $8 \pi\ m$ (circumference)

by proportion

Find the measure of θ by an arc of length 5 m

assume $\pi=3.1416$

$\frac{360}{8\pi}=\frac{\theta}{5}\\ \\ \theta=360*5/8\pi \\ \\ \theta=71.6\°$

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3 years ago

A right triangle has a hypotenuse length of 12, and one side length of 9. find the missing side length. do the side lengths form

Rina8888 [55]

Use the Pythagorean theorem:

$a^2+b^2=c^2$

c - a hypotenuse

a, b - legs

We have: a = 9 and c = 12. Substitute:

$9^2+b^2=12^2$

$81+b^2=144$ <em>subtract 81 from both sides</em>

$b^2=63\to b=\sqrt{63}\\\\b=\sqrt{9\cdot7}\\\\b=\sqrt9\cdot\sqrt7\\\\ \boxed{b=3\sqrt{7}}$

A Pythagorean triple consists of three positive integers a, b and c, such that

$a^2+b^2=c^2$ .

$b=3\sqrt{7}$ is not positive integer.

<h3>The sides of the triangle do not form a pythagorean triple.</h3>

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3 years ago