All categories

3 years ago

Please help!!!

1 answer:

5 0

Answer: Individuals can help in the earthquake disaster by 3 rules. The first rule is looking out for there neighbor if they see that they are stuck within the rubble of the earthquake . The second rule would to get yourself and your family out of the Quake zone. The third rule is always helping in a dire need like this one here if you are not able to help then please provide supplies to the teams that are willing to go searching for people. A community can not thrive on one man or woman they need all arms say if your home was destroyed in the quake I would hope your Community would be there to patch you up with there volunteers nobody can stand alone in this quake disaster if you do so then there is no Community .

You might be interested in

The _____, or center, of the earth consists of very hot metal, mainly iron mixed with some nickel.

Tom [10]

Crust is what we live on.
Mantle is under that.
Then at the very centre is the core.

So, B. Core

7 0

3 years ago

Which term do geographers use to classify an area with unifying physical characteristics

DanielleElmas [232]

Answer:

A physical Region is the term used by geographer to classify an area with unifying characteristics. Regions are areas that are extensively characterized by physical features, human influence and relationship between humanity and the environment. An example of a physical region is the Rocky Mountain in the west.

Explanation:

hopes this helps :)

3 0

2 years ago

O que é estrutura etária

Airida [17]

Idk plz spk english

8 0

3 years ago

What planet is the second largest and the second fastest spinning planet?

hodyreva [135]

The answer is Saturn

6 0

3 years ago

3. A space vehicle is traveling at 4300 km/h relative to Earth when the exhausted rocket motor (mass 4m) is disengaged and sent

kvv77 [185]

Answer: Vce= 4234.4km/hr or 1180m/s

Explanation:

Mass of rocket motor Mr= 4m

Mass of control module Mc= m

Initial velocity of spaceship relative to earth Vs= 4300km/hr

Final velocity of command module relative to the rocket motor Vrc = 82km/hr

Total mass of spaceship M= 4m+m= 5m

Using law of conservation of momentum;

MVs= MrVre + McVce eqn1

Vre = Vrc+Vce eqn2

Where Vce is velocity of control room relative to the earth and Vre is velocity of rocket motor relative to the earth

Substituting eqn2 to eqn1, we have.

MVs= Mr(Vrc+Vce) +McVce

MVs= MrVrc+MrVce+McVce

Making Vce the subject of formula.

Vce = (MVs-MrVrc)/(Mc+Mr)

Substituting the values we have,

Vce = (5m×4300km/hr - 4m×82km/hr)/ (m+4m)

Vce = 21172m/5m

Vce= 4234.4km/hr or 1180m/s

3 0

2 years ago