Add and SImplify (x+2)/(x) + (x-3)/(x+2)

1 answer:

7 0

(x+2)/(x) + (x-3)/(x+2)

Common denominator x(x+2)

Reduce both to common denominator:
x+2)/[x(x+2)] + (x-3)/[x(x+2)] ===> [(x+2)² + (x-3)] / [x(x+2)]
= [x²+4x+4+x-3] / [x(x+2)]
=[x²+54x+1] / [x(x+2)]

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1. Evaluate -3x^3 -2y^2 when x=-5 and y =3

-Dominant- [34]

Answer:

357

Step-by-step explanation:

A) We replace x = - 5 and u = 3 into -3x^3 -2y^2

and we have -3x^3 -2y^2= -3*(-5)^3 -2*3^2= -3*(-125)- 2*9

or -3x^3 -2y^2 = 375-18= 357

The answer is 357.

B) Replace h = -2 into h^2-3h+2

we have h^2-3h+2 = (-2)^2 -3*(-2) +2 = 4 +6 + 2= 12

The answer is 12

Have a good day.

8 0

3 years ago

The graph below shows the solution to which system of inequalities?

nlexa [21]

Answer:

Option D.

Step-by-step explanation:

Consider option D. $y\leq \frac{3x}{4}+10\,,\,y\leq \frac{-x}{2}-3$

Take point (0,0)

On putting this point in inequation $y\leq \frac{3x}{4}+10$ , we get

$0\leq 10$ which is true . So, solution is region towards the origin i,e region below the line $y= \frac{3x}{4}+10$ including the line itself .

On putting (0,0) in inequation $y\leq \frac{-x}{2}-3$ , we get $0\leq -3$ which is false , so solution is region away from the origin i.e region below line $y= \frac{-x}{2}-3$ including the line itself .