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2 years ago

Solution set of 5/11x+1/3=3/7-6/11x+3/7

1 answer:

6 0

$\frac{5}{11x} + \frac{1}{3} = \frac{3}{7} - \frac{6}{11x} + \frac{3}{7} \\ \frac{11}{11x} = \frac{6}{7} - \frac{1}{3} \\ \frac{1}{x} = \frac{11}{21} \\ x = \frac{21}{11} = 1 \frac{10}{11}$

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How to solve inequalities with word problems

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3 years ago

Please Help Will give 20 points

wariber [46]

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3 years ago

Complete the square 2x2- 12x+ 26 = 10

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4 0

3 years ago

Simplify . (1/c + 1/h)/(1/(c ^ 2) - 1/(r ^ 2))

Marrrta [24]

Answer:

$\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Step-by-step explanation:

$\frac{\frac{1}{c}+\frac{1}{h}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine $\frac{1}{c} + \frac{1}{h}$

$\frac{\frac{h+c}{ch}}{\frac{1}{c^2}-\frac{1}{r^2}}$

Combine the bottom, too.

$=\frac{\frac{h+c}{ch}}{\frac{r^2-c^2}{c^2r^2}}$

Apply the fraction rule

$=\frac{\left(h+c\right)c^2r^2}{ch\left(r^2-c^2\right)}$

Cancel

$=\frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

Therefore, $\frac{\left(\frac{1}{c}+\frac{1}{h}\right)}{\left(\frac{1}{\left(c^2\right)}-\frac{1}{\left(r^2\right)}\right)}:\quad \frac{\left(h+c\right)cr^2}{h\left(r^2-c^2\right)}$

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2 years ago

All of the following are true statements except _____.

shutvik [7]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

The false (wrong) equation among them is : A

$\qquad \sf \dashrightarrow \: | - 93| = - 93$

Because any number in a modulus comes out to be positive.

4 0

2 years ago