3rd one
Reason:
Point slope formula: y-y1=m(x-x1)
y1=-4
x1=1
m=1/2
Put it all together and you get a final answer of:
y-(-4)=1/2(x-1)
two negatives make one positive
so,
final answer:y+4=1/2(x-1)
Answer:
31.9secs
6,183.3m
Step-by-step explanation:
Given the equation that models the height expressed as;
h(t ) = -4.9t²+313t+269
At the the max g=height, the velocity is zero
dh/dt = 0
dh/dt = -9,8t+313
0 = -9.8t + 313
9.8t = 313
t = 313/9.8
t = 31.94secs
Hence it takes the rocket 31.9secs to reach the max height
Get the max height
Recall that h(t ) = -4.9t²+313t+269
h(31.9) = -4.9(31.9)²+313(31.9)+269
h(31.9) = -4,070.44+9,984.7+269
h(31.9) = 6,183.3m
Hence the maximum height reached is 6,183.3m
Answer:
As shown in picture, this is an isosceles right triangle ( A = 90 deg, B = C = 45 deg). => Except hypotenuse, side1 = side2, or x = 
Hope this helps!
:)
The answer to the question
