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3 years ago

How can Doug use place value pattern to check his answer?

Mathematics

1 answer:

MAVERICK [17]3 years ago

3 0

He can use it to make sure he lined his place values up properly

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You work for a carpet company. You sell carpets at these prices: 100 square feet for $67, 200 square feet for $130, 400 square f

Elanso [62]

Answer:

qué

Step-by-step explanation:

perdón no sé

5 0

3 years ago

Simplify: (4b + 3) (2b - 5).

igomit [66]

(4b+3) (2b−5)

(4b+3) (2b+−5)

(4b) (2b) + (4b) (−5) +(3) (2b) +(3) (−5)

8b²−20b+6b−15.

= 8b²−14b−15.

5 0

4 years ago

there are 60 new houses being built in a neighborhood. Last month, 2/3 of them were sold. This month, 2/5 of the remaining house

SIZIF [17.4K]

Sold Last Month: 60 x $\frac{2}{3}$ = 40

Remaining from last month: 60 - 40 = 20

Sold This Month: 20 x $\frac{2}{5}$ = 8

Remaining from this month: 20 - 8 = 12

Answer: there are 12 houses left to be sold

6 0

3 years ago

Annie gets a loan from her bank .She agrees yo borrow 8000 pounds at a fixed annual simple interest rate of 6%. She also agrees

mojhsa [17]

Annie paid 12800 pounds at end of 10 years

Solution:

Given that Annie borrows 8000 pounds at simple interest rate of 6 %

She also agrees to pay the loan back over a 10 year period

To find: total money paid back at the end of 10 years

The total amount paid is given as:

Total amount = simple interest + principal amount borrowed

The simple interest is given as:

$S.I = \frac{pnr}{100}$

Where, "p" is the principal sum

"n" is the number of years

"r" is the rate of interest

Here, p = 8000 ; r = 6 % ; n = 10 years

$S.I = \frac{8000 \times 10 \times 6}{100}\\\\S.I = 4800$

Therefore total amount paid at end of 10 years is:

Total amount = 4800 + 8000 = 12800

Thus Annie paid 12800 pounds at end of 10 years

6 0

3 years ago

What is a decomposition reaction?

yaroslaw [1]

Answer:

11-6√3 = a -b√3

where a=11 and b =6

Step-by-step explanation:

Step(i):-

Given

$\frac{5+2\sqrt{3} }{7+4\sqrt{3} }$

Rationalize

= $\frac{5+2\sqrt{3} }{7+4\sqrt{3} } X \frac{7-4\sqrt{3} }{7-4\sqrt{3} }$

= $\frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{7^{2} -(4\sqrt{3})^{2} }$

= $\frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{49-16(3) }$

= $\frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{1 }$

Step(ii):-

Multiply

${(5+2\sqrt{3})(7-4\sqrt{3} ) }$

= 5 × 7 - 5×4√3 + 2√3 ×7 - 2√3 × 4√3

= 35 -20√3+ 14√3-8×3

= 35 - 6√3 -24

= 11-6√3

6 0

3 years ago