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astraxan [27]
4 years ago
12

Express in the simplest radical form (NO DECIMALS).

Mathematics
1 answer:
kvv77 [185]4 years ago
7 0
\frac{6 \sqrt{15} }{5}
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Explorers on a planet with a thin atmosphere want to measure the acceleration of gravity at its surface. So they use a spring gu
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Answer:

The value of g_s is g_s=\frac{30}{21} \:\frac{m}{s^2}.

Step-by-step explanation:

We know that the position function is given by

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v(t)=\frac{d}{dt}(s(t))

So, the velocity function is

v(t)=\frac{d}{dt}(s(t))\\\\v(t)=\frac{d}{dt}(30t-\frac{g_s}{2} t^2)\\\\\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'\\\\v(t)=\frac{d}{dt}\left(30t\right)-\frac{d}{dt}\left(\frac{g_s}{2}t^2\right)\\\\v(t)=30-g_st

When a body reaches a vertical velocity of zero, this is the maximum height of the body and then gravity will take over and accelerate the object downward. Thus,

v(t)=30-g_st=0\\\\g_s=\frac{30}{t}

We know that the ball bearing reaches its maximum height 21 seconds after being launched (t = 21 s).

So, the value of g_s is g_s=\frac{30}{21} \:\frac{m}{s^2}.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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