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kolbaska11 [484]
2 years ago
7

IM GOING TO GIVE 251 POINTS TO WHOEVER ANSWER THIS PROBLEM.

Mathematics
1 answer:
Mariulka [41]2 years ago
4 0

Answer:

(x^87*(x^2+4))/54

Step-by-step explanation:

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On his last birthday, Arnie was 144 centimeters tall. Since that time, he has grown h centimeters. Which expression tells Arnie'
telo118 [61]

Answer:

H(M) = (1)M + 10

Step-by-step explanation:

6 0
3 years ago
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Please help, this is timed. 50 points for each answer. What is the difference quotient of f(x)?
egoroff_w [7]

x travels from -5 to 5

y stays constant at 8

Quotient is given by y/x

Hence our answer is .

\\ \sf\longmapsto \dfrac{8}{h}

Here h can't be 0 as it makes the diction undefined.

\\ \sf\longmapsto \dfrac{8}{h},h\neq 0

Option B

4 0
3 years ago
How to find the circumference using 3.14
TiliK225 [7]

Answer:

c = 2 * 3.14 * r    and     c = 3.14 * d

Step-by-step explanation:

The formulas for the circumference of a circle are

c = 2πr   and   c = πd

where r is the radius and d is the diameter

using π = 3.14

the formulas become

c = 2 * 3.14 * r    and     c = 3.14 * d

5 0
3 years ago
What is the y value of the vertex
Alenkasestr [34]

Answer:

y value = 49

Step-by-step explanation:

You are going to be completing the square

y = - x^2 - 10x + 24           Take a minus outside the brackets for the first 2 terms.

y = - (x^2 + 10x) + 24

Take 1/2 the linear term (1/2 10 and square it. Put that value inside the brackets. 1/2* 10 =5; 5^2 = 25

y = - (x^2 + 10x + 25) + 24

Add 25 outside the brackets.

y = -(x^2 + 10x + 25) + 24 + 25. You should stop here and consider why you are adding 25 outside the brackets. It is because there is a - sign in front of the trinomial and what is inside the brackets is really - 25 when the brackets are removed. Therefore to balance that, you add 25.

Now complete the square.

y = - ( x + 5)^2 + 49

The value you seek is 49.

=============

I'll confirm this with a graph.

4 0
4 years ago
NEED HELP ASAP WILL GIVE 5 STAR​
Dima020 [189]
27
I did this problem
6 0
3 years ago
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