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Pavel [41]
3 years ago
9

Which chemical equation represents a redox reaction? A. Mg(ClO3)2 + 2HCl → MgCl2 + 2HClO3 B. CO + H2O → H2 + CO2 C. 2NH4NO3 + Cu

Cl2 → 2NH4Cl + Cu(NO3)2 D. Na2SO3 + FeBr2 → 2NaBr + FeSO3
Chemistry
2 answers:
Svetlanka [38]3 years ago
7 0

The correct answer is option B, that is, CO + H2O → H2 + CO2

The redox reactions are regarded as the chemical reactions in which one reactant goes through the process of reduction and one reactant goes through the process of oxidation. The reduction reactions are the reactions in which gain of electrons occurs, while oxidation reactions are the reactions in which loss of electrons occurs.  

From the mentioned options, only option B, that is, CO + H2O → H2 + CO2 is a kind of redox reaction. In this, the carbon is getting oxidized from +2 to +4 oxidation state, and hydrogen is getting reduced from +1 to 0 oxidation state. Hence, this reaction can be regarded as a redox reaction.  


RUDIKE [14]3 years ago
4 0

Answer:

The correct answer is

B.  CO + H2O → H2 + CO2

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A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som
jek_recluse [69]

The question is incomplete, the complete question is:

A certain substance X has a normal freezing point of -6.4^oC and a molal freezing point depression constant K_f=3.96^oC.kg/mol. A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at -13.6^oC . Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.

<u>Answer:</u> The mass of glycine that can be dissolved is 1.3\times 10^2g

<u>Explanation:</u>

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m

OR

\text{Freezing point of pure solvent}=\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}           ......(1)

where,

Freezing point of pure solvent = -6.4^oC

Freezing point of solution = -13.6^oC

i = Vant Hoff factor = 1 (for non-electrolytes)

K_f = freezing point depression constant = 3.96^oC/m

m_{solute} = Given mass of solute (glycine) = ?

M_{solute} = Molar mass of solute (glycine) = 75.07 g/mol

w_{solvent} = Mass of solvent = 950. g

Putting values in equation 1, we get:

-6.4-(-13.6)=1\times 3.96\times \frac{m_{solute}\times 1000}{75.07\times 950}\\\\m_{solute}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\m_{solute}=129.66g=1.3\times 10^2g

Hence, the mass of glycine that can be dissolved is 1.3\times 10^2g

5 0
3 years ago
How many liters of 0.98 M have solution would react completely with 3.5 moles ca(oh)2
jasenka [17]

The question is typed wrong. Assuming the correct question is

How many liters of 0.98 M H2SO4 solution would react completely with 3.5 moles Ca(OH)2 ?

Answer:-

3.571 litres

Explanation:-

The balanced chemical equation for this reaction is

H2SO4 + Ca(OH)2 = CaSO4 + 2 H2O

From the balanced chemical equation we see that

1 mole of Ca(OH)2 reacts with 1 mol of H2SO4.

∴3.5 moles of Ca(OH)2 reacts with 1 x 3.5 / 1 = 3.5 mol of H2SO4.

Strength of H2SO4 = 0.98 M

Volume of H2SO4 required = Number of moles of H2SO4 / Strength of H2SO4

= 3.5 moles / 0.98 M

= 3.571 litre

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What are two physical characteristics of ionic compounds?
ElenaW [278]

Answer:

high melting and boiling points

Explanation:

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