Answer:
33.6 mol of the atom strontium contains approximately
3) 2.02 × 10²⁵ atoms of strontium
Explanation:
The number of atoms in one mole of a substance is given by Avogadro's number number, 
, which is presented as follows;
1 mole of a substance contains = 6.022 × 10²³ elementary particles
33.6 mol of a substance will contain 33.6 × 6.02214 × 10²³ elementary particles of the substance
Therefore;
33.6 mol of the atom strontium contains 33.6 × 6.02214 × 10²³ = 2.023439 × 10²⁵ atoms of strontium
33.6 mol of the atom strontium contains ≈ 2.02 × 10²⁵ atoms of Sr.
Answer:
The answer to your question is below
Explanation:
Material Classification Reason
Crude oil Mixture Because we know that crude oil
is composed of different substances.
Butane Compound Because it is composed of carbon
and hydrogen
Dodecane Compound Because it is composed of carbon
and hydrogen.
Octane Compound Because it is composed of carbon and
hydrogen.
Benzene Compound It is also composed of carbon and
hydrogen.
Gasoline Mixture It is a combination of hydrocarbons
Kerosene Mixture It is a combination of hydrocarbons
Oxygen Element We can find it in the periodic table.
Carbon dioxide Compound It is composed of carbon and oxygen.
Water Compound It is composed of hydrogen and
oxygen.
Answer:
4.27
Explanation:
Let's consider the dissociation of a generic monoprotic acid.
HA(aq) → H⁺(aq) + A⁻(aq)
The pH is 2.36. The concentration of H⁺ is:
pH = -log [H⁺]
[H⁺] = antilog -pH
[H⁺] = antilog -2.36 = 4.37 × 10⁻³ M
We know that the concentration of the acid Ca = 0.3535 M. We can find the acid dissociation constant using the following expression.
[H⁺] = √(Ca × Ka)
Ka = [H⁺]²/Ca
Ka = (4.37 × 10⁻³)²/0.3535
Ka = 5.40 × 10⁻⁵
The pKa is:
pKa = -log Ka = -log 5.40 × 10⁻⁵ = 4.27
Answer:
the symbol that is missing might be 2.
Explanation:
I am not 100% on this, so correct me if I am wrong.
Answer:
See explanation
Explanation:
The overall charge on ClO3− is shown on the image attached to this answer. If we calculate the formal charges on each atom in the structure, we will notice that one oxygen atom has a formal charge of -1 while all other atoms have a formal charge of zero.
This gives the compound an overall charge of -1 as shown in the image attached to this answer. This is the correct Lewis structure for the compound ClO3− .
