Help plz if right u get brainlist

Estimate the answer to:<br> 341 ÷ 0.28

Snezhnost [94]

Answer:

341 ÷ 0.28=1217,85714286

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

John earns $7.50 per hour at his job. Becky's earnings are given by the equation P = 8.25x, where P is her

hodyreva [135]

In 9 hours
john earns $67.5
becky earns $74.25
becky earns $6.75 more than john

4 0

3 years ago

In the diagram A, B, and C are the points on the circle. Use the diagram to prove the theorem which states that:

nevsk [136]

9514 1404 393

Explanation:

Here's one way to go at it.

Draw segments AB and CO. Define angles as follows. (The triangles with sides that are radii are all isosceles, so their base angles are congruent.)

x = angle OAB = angle OBA

y = angle OAC = angle OCA

z = angle OBC = angle OCB

Consider the angles at each of the points A, B, C.

At A, we have ...

angle CAB = x + y

At B, we have ...

angle CBA = x + z

At C, we have ...

angle ACB = y + z

The sum of the angles of triangle ABC is 180°, as is the sum of angles in triangle ABO. This gives ...

x + x + ∠AOB = (x+y) +(x+z) +(y+z)

∠AOB = 2(y+z) = 2∠ACB

This shows ∠AOB = 2×∠C, as required.

8 0

3 years ago

Marty is spending money at the average rate of $3 per day. After 14 days he has $68 left.

slega [8]

A) 110 - (3 × 14x) = 68
B) 3×14 is 42 so he spent $42 in two weeks 42+68= 110 so he had $110 to begin with
C) he will run out of money in about 22 days (22.6666666667)

4 0

3 years ago

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Waiting on the platform, a commuter hears an announcement that the train is running five minutes late. He assumes the arrival ti

natima [27]

Answer:

D. 91%

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Less than 15 minutes.

Event B: Less than 10 minutes.

We are given the following probability distribution:

$f(T = t) = \frac{3}{5}(\frac{5}{t})^4, t \geq 5$

Simplifying:

$f(T = t) = \frac{3*5^4}{5t^4} = \frac{375}{t^4}$

Probability of arriving in less than 15 minutes:

Integral of the distribution from 5 to 15. So

$P(A) = \int_{5}^{15} = \frac{375}{t^4}$

Integral of $\frac{1}{t^4} = t^{-4}$ is $\frac{t^{-3}}{-3} = -\frac{1}{3t^3}$

Then

$\int \frac{375}{t^4} dt = -\frac{125}{t^3}$

Applying the limits, by the Fundamental Theorem of Calculus:

At $t = 15$ , $f(15) = -\frac{125}{15^3} = -\frac{1}{27}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A) = -\frac{1}{27} + 1 = -\frac{1}{27} + \frac{27}{27} = \frac{26}{27}$

Probability of arriving in less than 15 minutes and less than 10 minutes.

The intersection of these events is less than 10 minutes, so:

$P(B) = \int_{5}^{10} = \frac{375}{t^4}$

We already have the integral, so just apply the limits:

At $t = 10$ , $f(10) = -\frac{125}{10^3} = -\frac{1}{8}$

At $t = 5$ , $f(5) = -\frac{125}{5^3} = -1$

Then

$P(A \cap B) = -\frac{1}{8} + 1 = -\frac{1}{8} + \frac{8}{8} = \frac{7}{8}$

If given the train arrived in less than 15 minutes, what is the probability it arrived in less than 10 minutes?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{\frac{7}{8}}{\frac{26}{27}} = 0.9087$

Thus 90.87%, approximately 91%, and the correct answer is given by option D.

3 0

3 years ago