Question

Write a sine function with the given amplitude, period, phase shift, and vertical shift.

Answer 1

Answer:

$y = 2 sin (\frac{2x- 1}{16 \pi} ) - 1$

Step-by-step explanation:

We know that the standard form of equation for the sine function is given by:

$y = Asin(Bx-C)$ where $A$ is amplitude, period is $\frac{2\pi }{B}$ and the phase shift is equal to $Bx-C$ set to zero. $C$ is then obtained by this equation.

Here in this problem: A is equal to 2, period=2π/B=2π/2=π, where B is equal to 2 and the phase shift is equal to 2x - 1/16 pi = 0.

$y = 2 sin (\frac { 2 x - 1 } { 16 \pi} ) - 1$