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vagabundo [1.1K]
4 years ago
7

Approximately how many times greater is 2.3x10^-4 than 1.15x10^-8 ?

Mathematics
1 answer:
Minchanka [31]4 years ago
3 0

Answer:

2.3 × 10^{-4} is 20,000 times greater than 1.15 × 10^{-8}

Step-by-step explanation:

Given as :

The first number= x = 2.3 × 10^{-4}

The second number= y = 1.15 × 10^{-8}

Let The first number is z times greater than second number

i.e x = z × y

Or, z = \dfrac{x}{y}

Or, z = \dfrac{2.3\times 10^{-4}}{1.15\times 10^{-8}}

Or, z = 2 × 10^{4}

∴  z = 20,000

So,The first number is 20,000 times greater than second number

Hence, 2.3 × 10^{-4} is 20,000 times greater than 1.15 × 10^{-8} . Answer

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ZX and zy are supplementary angles. zy measures 33°.what is the measure of ZX
Sati [7]

Answer:

147°

Step-by-step explanation:

supplementary angles equal to 180° in total so...

180 - 33 = 147

8 0
3 years ago
50 POINTS HELP NOW<br><br> Find the logarithm base 10 of each number: <br> 10
beks73 [17]

The logarithm base 10 of the number 10 is 1

<h3>How to solve logarithm ?</h3>

We have to find logarithm base 10 of number 10.

Therefore, using logarithm rule

logₐ a = 1

Hence,

log₁₀ 10 = 1

Therefore, logarithm base 10 of the number 10 is 1

learn more on logarithm here: brainly.com/question/13594713

#SPJ1

4 0
2 years ago
Beyonce is solving a system of equations:
aivan3 [116]

Answer:

x=5, y=4. (5, 4).

Step-by-step explanation:

2x-3y=-2

4x+y=24

------------------

-2(2x-3y)=-2(-2)

4x+y=24

----------------------

-4x+6y=4

4x+y=24

--------------

7y=28

y=28/7

y=4

4x+4=24

4x=24-4

4x=20

x=20/4

x=5

8 0
3 years ago
Please help! I've been working on this for a few days and I just don't understand, it's due in a few hours. Thank you.
never [62]

Answer:

Part A: α = arc tan (y/x) = tan⁻¹ (y/x)

Part B: quadrant II α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 180°>α>90°

            quadrant III α = arc tan (-y)/(-x) = arc tan (y/x) = tan⁻¹ (y/x) 270°>α>180°

            quadrant IV α = arc tan (- y/x) = arc (- tan (y/x)) = - tan⁻¹ (y/x) 360°>α>270°

Part C: quadrant II 180°>α>90°  α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 180° - 80.53° = 99.47°

Step-by-step explanation:

PART A:

In this case we will use trigonometric function tanα to calculate angle α:

tanα = y/x => α = arc tan (y/x) = tan⁻¹ (y/x)

This formula is use in general way and in first quadrant  90°>α>0°

Part B:

But in the other quadrants you must know to use unit circle to reduce angle from II, III and IV quadrant to the first quadrant.

If angle is in the quadrant II  180°>α>90° then

tanα = - tan (180°-α)

If angle is in the quadrant III  270°>α>180° then

tanα = tan (α-180°)

If angle is in the quadrant IV  360°>α>270° then

tanα =- tan (360°-α)

Part C:

vector w (x,y) = (-1,6) this vector lies in quadrant II      180°>α>90°

180°- α = tan⁻¹ (-6/1) = - tan⁻¹ 6 = 80.53°  => 180° - α = 80.53°

α = 180° - 80.53 = 99.47°

It's not easy to understand this, but it's not easy for me to explain.

God with you!!!

5 0
3 years ago
Write in slope intercept form of an equation of the line through (5,-2) with a slope of 3/5
aliina [53]
Hope it helps :))
Here is the working

5 0
3 years ago
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