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Hunter-Best [27]
4 years ago
10

Someone plz help I need this answer quick !

Mathematics
1 answer:
Ivahew [28]4 years ago
8 0
The answer is 5 months, with the cost of $85. You can find this answer by first writing the charges as 12x + 25 and 10x + 35. Then, you set them equal to each other and solve to find x, which is the number of months.
12x + 25 = 10x + 35
- 10x
2x + 25 = 35
- 25
2x = 10
÷ 2
x = 5

Now that we know what x is, we can substitute it in and get 10(5) + 35 = 50 + 35 = 85.
I hope this helps!
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40 degree, 3x, and 4x solve for x
Alex73 [517]

Answer:

The value of x would be 20

Step-by-step explanation:

To solve this triangle, we need to first note that all triangles have 180 degrees. So we can add these all together and set equal to 180.

40 + 3x + 4x = 180

40 + 7x = 180

7x = 140

x = 20

8 0
4 years ago
Karl set out to Alaska in his truck.
Ivenika [448]

Considering the linear function described, 500 liters of fuel were initially in the tank.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

  • m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.
  • b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

Researching this problem on the internet and looking at the graph, we have that when x = 0, y = 500, that is, the y-intercept is of 500. From the bullet points, the y-intercept is the initial value, hence 500 liters of fuel were initially in the tank.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

8 0
2 years ago
Use the quadratic formula to solve each equation.
Elden [556K]

Answer:

1) x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}

x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}

2) x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}

x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}

3) p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}

p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}

4) y_1 = \frac{-3 - 9}{4}=-3

y_2 = \frac{-3 + 9}{4}= \frac{3}{2}

Step-by-step explanation:

The quadratic formula is given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

We can use this formula in order to solve the following equations:

1. x^2 − 2x = 12 → a = 1, b = −2, c = −12

For this case if we apply the quadratic formula we got:

x = \frac{-(-2) \pm \sqrt{(-2)^2 -4(1)(-12)}}{2(1)}

x_1 = \frac{2 - 2\sqrt{13}}{2}= 1-\sqrt{13}

x_2 = \frac{2 + 2\sqrt{13}}{2}= 1+\sqrt{13}

2. 1/2x^2 − 6x = 2 → a = 1 / 2, b = −6, c = −2

For this case if we apply the quadratic formula we got:

x = \frac{-(-6) \pm \sqrt{(-6)^2 -4(1/2)(-2)}}{2(1/2)}

x_1 = \frac{6 - 2\sqrt{10}}{1}= 6-2\sqrt{10}

x_2 = \frac{6 + 2\sqrt{10}}{1}= 6+2\sqrt{10}

3. 2p^2 + 8p = 7 → a = 2, b = 8, c = −7

For this case if we apply the quadratic formula we got:

p = \frac{-(8) \pm \sqrt{(8)^2 -4(2)(-7)}}{2(2)}

p_1 = \frac{-8 - 2\sqrt{30}}{4}= -2-\frac{1}{2}\sqrt{30}

p_2 = \frac{-8 + 2\sqrt{30}}{4}= -2+\frac{1}{2}\sqrt{30}

4. 2y^2 + 3y − 5 = 4 → a = 2, b = 3, c = −9

For this case if we apply the quadratic formula we got:

y = \frac{-(3) \pm \sqrt{(3)^2 -4(2)(-9)}}{2(2)}

y_1 = \frac{-3 - 9}{4}=-3

y_2 = \frac{-3 + 9}{4}= \frac{3}{2}

8 0
4 years ago
Use property to find sum pr product 5 x 23 x 2
zloy xaker [14]
5\times23\times2\\\\use\ commutative\ property:\ a\times b=b\times a\\\\23\times5\times2\\\\use\ associative\ property:(a\times b)\times c=a\times(b\times c)\\\\23\times(5\times2)=23\times10=\huge\boxed{230}
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3 years ago
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IrinaVladis [17]

Answer:

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