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malfutka [58]
3 years ago
9

3. Find the angle between the given vectors to the nearest tenth of a degree.

Mathematics
1 answer:
Dima020 [189]3 years ago
6 0

Answer:

Step-by-step explanation:

u.v=|u||v| cos \theta\\(8)(9)+(7)(7)=\sqrt{8^2+7^2 } \sqrt{9^2+7^2} cos \theta\\72+49=\sqrt{64+49} \sqrt{81+49}~ cos ~\theta\\121=\sqrt{113} \sqrt{130} ~cos~\theta\\cos~\theta=\frac{121}{\sqrt{113} \sqrt{130} } \\\theta=cos^{-1} (\frac{121}{\sqrt{113}\sqrt{130}  } )\approx 3.3^\circ

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Answer:

D) x^3+8y^6

Step-by-step explanation:

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D) x^3+8y^6

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Basically we need to check which one of the given choices can be represented in cubic form along with addition sign.

3 and 9 can't be written in cubic form unless we use radical numbers.

So the only choice left is D)

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3 years ago
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