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3 years ago

I need help with this question. will give brainliest

Mathematics

2 answers:

alisha [4.7K]3 years ago

7 0

I think it would be option (D).

inessss [21]3 years ago

6 0

Your answer is d hope this helps

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Suppose the volume of a right circular cylinder is 225 cubic meters and the area of its base is 25 square meters. What is the he

JulijaS [17]

base area = 25 sq meters
area = PI*radius^2
radius = sq root [area / PI]
radius = sq root (25/PI)
base radius = 2.8209479177 meters

Cylinder Volume = π • r² • height
Therefore,
Cylinder height = Volume / [pi*radius^2]
Cylinder height = 225 / [PI*2.8209479177 ^ 2]
Cylinder height = 225 / [PI * 7.9577471544 ]
Cylinder height = 225 / 25
Cylinder height = 9 meters

Source:
Formulas
http://www.1728.org/diamform.htm
Calculator
http://www.1728.org/diam.htm

6 0

3 years ago

Read 2 more answers

FAST!! !!!!!!!!!!!!!!!!!!!!!!!!!!!!

omeli [17]

Answer:

See the net of the prism in the attachment

It has 6 faces with sizes:

Two off 4 in x 25 in
Two off 7 in x 25 in
Two off 4 in x 7 in

6 0

3 years ago

Read 2 more answers

One leg of a 45°-45°-90° triangle measures 9sqrt2 inches. What is the length of the hypotenuse?

stiv31 [10]

We know that
a=9√2
b=9√2
a=b---------- for having both angles of 45
c²=a²+b²-------> (9√2)²+(9√2)²------>(324)-----------> c=√324=18

the answer is the option A 18 inches

8 0

4 years ago

If the quadratic formula is used to find the solution set of 3x2 + 4x - 2 = 0, what are the solutions?

7nadin3 [17]

Answer:

$x=\frac{-2}{3} \pm \frac{\sqrt{10}}{3}$

Step-by-step explanation:

Compare $ax^2+bx+c$ to $3x^2+4x-2$ .

We have $a=3,b=4,c=-2$ .

The quadratic formula is for solving equations of the form $ax^2+bx+c=0$ and is $x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$ .

So we are going to plug in our values in that formula to find our solutions,x.

If you want to notice it in parts you can.

Example I might break it into these parts and then put it in:

Part 1: Evaluate $b^2-4ac$

Part 2: Evaluate $-b$

Part 3: Evaluate $2a$

------Let's do these parts.

Part 1: $b^2-4ac=(4)^2-4(3)(-2)=16-12(-2)=16+24=40$ .

This part 1 is important in determining the kinds of solutions you have. It is called the discriminant. If it is positive, you have two real solutions. If it is negative, you have no real solutions (both of the solutions are complex). If it is 0, you have one real solution.

Part 2: $-b=-4$ since $b=4$ .

Part 3: $2a=2(3)=6$ .

Let's plug this in:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$

or in terms of our parts:

$x=\frac{\text{Part 2} \pm \sqrt{\text{Part 1}}}{\text{Part 3}}$

$x=\frac{-4 \pm \sqrt{40}}{6}$

40 itself is not a perfect square but it does contain a factor that is. That factor is 4.

So we are going to rewrite 40 as $4 \cdot 10$ .

$x=\frac{-4 \pm \sqrt{4 \cdot 10}}{6}$

$x=\frac{-4 \pm \sqrt{4} \cdot \sqrt{10}}{6}$

$x=\frac{-4 \pm 2\cdot \sqrt{10}}{6}$

I'm going to go ahead and separate the fraction like so:

$x=\frac{-4}{6} \pm \frac{2 \cdot \sqrt{10}}{6}$

Now I'm going to reduce both fractions:

$x=\frac{-2}{3} \pm \frac{1 \cdot \sqrt{10}}{3}$

$x=\frac{-2}{3} \pm \frac{\sqrt{10}}{3}$

6 0

3 years ago

Identify a possible pattern. Use the pattern to write the next three numbers 152,137,122....

Mama L [17]

You basically subtract 15 from a number then continue doing it each time

So 152, 137, 122, 107, 92, 77...

Another way to tell is if you minus 137 from 152, its 15

Do that again to the next number which is 137 minus 122 and its 15.

You can do this just to check and make sure you are doing it right

Answer: The pattern is subtracting 15 from each number as you go along the pattern.

6 0

4 years ago