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ale4655 [162]
3 years ago
6

Can you guys tell me which ones are independent varibles or dependent varibles

Mathematics
1 answer:
Mrrafil [7]3 years ago
8 0

the x s are the independent variable so any direct change to them is changing the independent.  like the second one has -5 on the x

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I want to know how to sole a math problem which is 8-3/2/3
Elodia [21]
Are there any parenthesis? I think you might have skipped out on them.
6 0
3 years ago
I literally don’t get this I need the answer
Ksju [112]

Answer:

62.83 units^{3}

Step-by-step explanation:

The equation is V(Volume) equals π (Pi/3.14) multiplied by r(radius) squared multiplied by h(height). The way it would be written out is V=π×r^{2}×h. So when you plug in the radius (2) and the height (5) you get π×2^{2}×5 which equals 62.83185 or 62.83. I hope this helps you understand and if you need more help let me know.

6 0
2 years ago
What is 69 devided by 69<br> Can yah help and add me
kotykmax [81]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it
natima [27]

Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, h_o=5\ ft

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

h=-16t^2+vt+h_0

Putting all the values,

h=-16t^2+60t+5 .....(1)

For maximum height, put

\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s

Put t = 1.875 in equation (1)

h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m

So, the maximum height reached by the ball is 61.25 m.

8 0
3 years ago
F(2)=20(1.25)^x<br> STEP BY STEP
Nezavi [6.7K]
F(2) = 20(1.25)^x

f(2) = 20(1.25)^2 - plug in 2 to x

f(2) = 20(1.5625) - calculate 1.25^2

f(2) = 31.25 - simplify
4 0
3 years ago
Read 2 more answers
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