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ladessa [460]
3 years ago
9

Which decimal number is equal to 2/3? 0.6 0.66 0.6....... 0.67

Mathematics
2 answers:
ICE Princess25 [194]3 years ago
7 0
Hello there!

All you have to do next time is take a calculator and divide 2 by 3. Then the number the calculator shows you is the answer.

When we divide 2 by 3, it equals to 0.666666667

So, the correct answer is option C
Roman55 [17]3 years ago
4 0
2/3 = .66
Hope this helps!!
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The volumes of two similar figures are 27 mm^3 and 1331 mm^3. If the surface area of the smaller figure is 18 mm^2, what is the
trasher [3.6K]
Volumes are in ratio 27 : 1331
so ratio od individual lengths  = cube roots  = 3 : 11
and surface areas will be in the ratio  3^2 : 11^2 = 9:121

so surface area of the larger figure  is  121 * 18  / 9  =  242 mm^2
7 0
3 years ago
Can somebody please tell me if this is correct or not​
valentinak56 [21]

Answer:

I would have done it the same way. Believing it is correct.

Step-by-step explanation:

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What is the proportional numbers of 26/13
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eboi

Step-by-step explanation:

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If frequency of being late is .15 how often late in 100
koban [17]
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3 years ago
In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is
zheka24 [161]

Answer:

f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

Step-by-step explanation:

Let:

M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y

This is and exact equation, because:

\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}

So, define f(x,y) such that:

\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)

The solution will be given by:

f(x,y)=C_1

Where C1 is an arbitrary constant

Integrate \frac{\partial f(x,y)}{\partial x} with respect to x in order to find f(x,y):

f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}

Substitute into \frac{\partial f(x,y)}{\partial y} =N(x,y)

2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y

Integrate \frac{dg(y)}{dy} with respect to y:

g(y)=\int\ {8y} \, dy =4y^2

Substitute g(y) into f(x,y):

f(x,y)=2x^2+4y^2+2xy

The solution is f(x,y)=C1

f(x,y)=2x^2+4y^2+2xy=C_1

Solving y using quadratic formula:

y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )

4 0
3 years ago
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