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3 years ago

Please answer the question from the attachment.

Mathematics

1 answer:

alekssr [168]3 years ago

5 0

The correct answer is 43.75

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Tell whether ΔABC and ΔDCB can be proven congruent.

Vikentia [17]

Answer:

D. No, there isn’t enough information because only two pairs of corresponding sides can't be used to prove that two triangles are congruent.

4 0

2 years ago

A cube has a net with area 600 in2. How long is an edge of the cube?

aev [14]

Answer : The length of an edge of cube is, 10 inches.

Step-by-step explanation :

The formula used for area of cube is:

Area of cube = $6a^2$

where,

a = edge

We are given that:

Area of cube = $600in^2[tex]Now put all the given values in the above formula, we get:Area of cube = [tex]6a^2$

$600in^2=6a^2$

$a=10inches$

Therefore, the length of an edge of cube is, 10 inches.

3 0

4 years ago

How do i do standerd form

katrin2010 [14]

Standard form is the same as numerical form
e.g: thirty-five in standard form=35

<span>Hope this helps</span>

4 0

3 years ago

At the movies, tickets cost $13.50 for adults and $4.50 for kids under 12. What would

Pie

Answer:

adult-135

kid-27

Step-by-step explanation:

13.50*10=135

4.50*6=27

7 0

3 years ago

The given line passes through the points (0, -3) and (2, 3).

puteri [66]

The equation, in point-slope form of the line that is parallel to the given line and passes through the point (-1, -1) is y + 1 = 3(x + 1).

<u>Solution:</u>

Given that, a line passes through (0, -3) and (2, 3).

We have to find the line equation which is parallel to above line and passes through (-1, -1).

Now, let us find the slope of the given line.

$\text { slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}, \text { where }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are points on that line }$

$\text { Then, } m=\frac{3-(-3)}{2-0}=\frac{3+3}{2}=\frac{6}{2}=3$

So, slope of given line is 3,

Then, slope of required line is also 3, as slopes of parallel lines are equal.

Then, required line equation in point – slope form is given as:

$\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right)} \\\\ {y-(-1)=3(x-(-1))} \\\\ {\rightarrow y+1=3(x+1)}\end{array}$

Hence, the line equation is y + 1 = 3(x + 1).

6 0

4 years ago