1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elena-s [515]
3 years ago
14

Need help on this question

Mathematics
1 answer:
bazaltina [42]3 years ago
3 0
Hello,
Please, see the attached file.
Thanks.

You might be interested in
Jaylah has two packages of trail mix. The first package weighs 2.40 pounds and the second package weighs 3.25 pounds. She mixes
navik [9.2K]
She can make up to 22 bags because you have to add 2.40 and 3.25 together to get 5.65 then divide by .25 to get 22.6 she can make a total of 22 with .6 left over
7 0
3 years ago
Can someone tell me the volume of this? lolz​
Black_prince [1.1K]

Answer:

V=πr2h=π·62·8≈904.77868

Step-by-step explanation

6 0
3 years ago
What are the answers plz help me
Ghella [55]
Number 3 is 9 not negative 10
8 0
3 years ago
Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu
tia_tia [17]

Answer:

The minimum head breadth that will fit the clientele is 4.4 inches.

The maximum head breadth that will fit the clientele is 7.8 inches.

Step-by-step explanation:

Let <em>X</em> = head breadths of men that is considered for the helmets.

The random variable <em>X</em> is normally distributed with mean, <em>μ</em> = 6.1 and standard deviation, <em>σ</em> = 1.

To compute the probability of a normal distribution we first need to convert the raw scores to <em>z</em>-scores using the formula:

z=\frac{x-\mu}{\sigma}

It is provided that the helmets will be designed to fit all men except those with head breadths that are in the smallest 4.3% or largest 4.3%.

Compute the minimum head breadth that will fit the clientele as follows:

P (X < x) = 0.043

⇒ P (Z < z) = 0.043

The value of <em>z</em> for this probability is:

<em>z</em> = -1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\-1.717=\frac{x-6.1}{1}\\x=6.1-(1.717\times 1)\\x=4.383\\x\approx4.4

Thus, the minimum head breadth that will fit the clientele is 4.4 inches.

Compute the maximum head breadth that will fit the clientele as follows:

P (X > x) = 0.043

⇒ P (Z > z) = 0.043

⇒ P (Z < z) = 1 - 0.043

⇒ P (Z < z) = 0.957

The value of <em>z</em> for this probability is:

<em>z</em> = 1.717

*Use a <em>z</em>-table.

Compute the value of <em>x</em> as follows:

z=\frac{x-\mu}{\sigma}\\1.717=\frac{x-6.1}{1}\\x=6.1+(1.717\times 1)\\x=7.817\\x\approx7.8

Thus, the maximum head breadth that will fit the clientele is 7.8 inches.

5 0
3 years ago
1. Mariana took 50 minutes to complete her math assignment. She took 2 minutes to solve each problem and 10 minutes to check her
Anarel [89]

Answer:

D

Step-by-step explanation:

It's the only thing not listed aka the number of math problems.

6 0
3 years ago
Other questions:
  • Which of these figures has rotational symmetry?
    8·2 answers
  • The length of a stalactite​ (in mm) has been measured at the beginning of every fourth year since the year 2000. the data throug
    8·1 answer
  • If the measure of a triangle are in the ratio 2:5:5. What is the measure of the angle
    15·1 answer
  • What is the answer to x+a=3/4
    10·1 answer
  • clarify each function as a linear function, a linear absolute value function, a quadratic function, or an exponential function
    15·1 answer
  • Density is mass divided by volume. Find the density of an aluminum block with a mass of 35 grams and a volume of 14 cm3?.
    12·1 answer
  • Whats 6% tax on $320.90
    5·2 answers
  • What is the missing reason in the proof?
    6·1 answer
  • Jimmy’s family moved to a tropical climate. For the year that followed, he recorded the number of days that had a temperature ab
    11·2 answers
  • Find the following arc measures for question 2
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!