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When doctors prescribe medicine, they must consider how the drug’s effectiveness declines as time passes. If each hour a drug is

Dima020 [189]

Answer:

<u>The total time for the initial dose of 500 mg to reach a level of 150 mg is approximately 11 hours and 27 minutes </u>

Step-by-step explanation:

Initial dose = 500 mg

Let's calculate the effectiveness of the drug hour by hour, this way:

After 1 hour: 90% of 500 = 450 mg

After 2 hours: 90% of 450 = 405 mg

After 3 hours: 90% of 405 = 364.5 mg

After 4 hours: 90% of 364.5 = 328.05 mg

After 5 hours: 90% of 328.05 = 295.25 mg

After 6 hours: 90% of 295.25 = 265.73 mg

After 7 hours: 90% of 265.73 = 239.16 mg

After 8 hours: 90% of 239.16 = 215.24 mg

After 9 hours: 90% of 215.24 = 193.72 mg

After 10 hours: 90% of 193.72 = 174.35 mg

After 11 hours: 90% of 174.35 = 156.92 mg

After 12 hours: 90% of 156.92 = 141.23 mg

Difference between 11 and 12 hours: 156.92 - 141.23 = 15.7 mg

Difference per minute between 11 and 12 hours: 15.7/60 = 0.262 mg

Time to reach a level of 150 mg in minutes after 11 hours = (156.92-150)/0.262

Time to reach a level of 150 mg in minutes after 11 hours = 26.4

<u>The total time for the initial dose of 500 mg to reach a level of 150 mg is approximately 11 hours and 27 minutes </u>

4 0

3 years ago

3,969 + b^2 = 11,025

ludmilkaskok [199]

Answer:

b=84

Step-by-step explanation:

from your equation, subtract 3969 from each side

you are left with b^2=7056

sqrt b^2 = sqrt 7056

b=84

7 0

3 years ago

Read 2 more answers

What is 1^∞ equal to?

Alex Ar [27]

The result is undefined.

7 0

3 years ago

What is the frequency of a wave that has a wave speed of 30 m/s and a wavelength of 0.60 m?

maksim [4K]

Answer:

wave length = 30/6 = 5m

Step-by-step explanation:

wave travels 30m in one second.

wave completes 6 cycles in one second.

7 0

3 years ago

Read 2 more answers

The function f(x) = –x2 – 4x + 5 is shown on the graph. On a coordinate plane, a parabola opens down. It goes through (negative

sertanlavr [38]

The true statement about the function f(x) = -x² - 4x + 5 is that:

The range of the function is all real numbers less than or equal to 9.

<h3 /><h3>What is the domain and range for the function of y = f(x)?</h3>

The domain of a function is the set of given values of input for which the function is valid and true.

The range is the dependent variable of a given set of values for which the function is defined.

The domain of the function: f(x) = -x² - 4x + 5 are all real number from -∞ to +∞

For a parabola ax² + bx + c with the vertex $\mathbf{(x_v,y_v)}$

If a < 0, then the range is f(x) ≤ $\mathbf{y_v}$

If a > 0, then the range f(x) ≥ $\mathbf{y_v}$

Here; a = -1,

The vertex for an up-down facing parabola for a function y = ax² + bx + c is:

$\mathbf{x_v = -\dfrac{b}{2a}}$

Thus,

vertex $\mathbf{(x_v,y_v)}$ = (-2, 9)

Range: f(x) ≤ 9

Therefore, we can conclude that the range of the function is all real numbers less than or equal to 9.

Learn more about the domain and range of a function here:

brainly.com/question/26098895

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5 0

2 years ago