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4 years ago

Round to the nearest tenth place it is repeating decimal 4/6

Mathematics

1 answer:

Scilla [17]4 years ago

8 0

Answer:

0.7

Step-by-step explanation:

I divided 4 by 6

0.6666666666666...

Simplify to 0.7

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Thirty and 25 hundredths in decimal form

Zolol [24]

30.25. Thirty is the whole number, therefore it goes before the decimal. The 25 hundredths come after the decimal. The first Slot after the decimal is the tenths. And the second is the hundredths. .25 is twenty five hundredths.

4 0

3 years ago

The surface area of a sphere of radius r is S, where = 4

grandymaker [24]

Answer:

r=√( s )

4π

Step-by-step explanation:

S= 4πr^2

That is the formula for the surface area of a sphere .

first divide through by 4π and take the square root of both sides

8 0

3 years ago

Please help due tomorrow for Questions C. (A),(B)

8090 [49]

A.
Selena makes 0.05 posters per minute
Jason makes 0.2 posters per minute
Kai makes 0.2 posters per minute
Enrique makes 0.1 posters per minute
Andre makes 0.5 posters per minute

B.
Selena makes the least posters per minute
Andre makes the most posters per minute

C.
If Selena made 80 posters in 8 minutes, she would be making 10 posters per minute.
Selena now makes the most posters and Enrique makes the least.

Hope this helps!! :)

8 0

4 years ago

The fourth term of a sequence is 108. Each term after the first is 3 times the previous term. Write an explicit expression that

marishachu [46]

Answer:

$f(n)=4(3)^{n-1}$

Step-by-step explanation:

Let the first term be $x$ , then the terms of the sequence are:

$x,3x,9x,27x,81x,...$ .

Since the fourth term is 108, we have

$27x=108$

$\implies x=4$

Hence the sequence becomes:

$4,12,36,108,324,...$ .

The explicit expression for a geometric expression is given by:

$f(n)=ar^{n-1}$

where a=4 and r=3

The required formula is:

$f(n)=4(3)^{n-1}$

8 0

3 years ago

Please answer ASAP I will give you brainliest

RideAnS [48]

Answer:

a = 11

b = 6

Step-by-step explanation:

$\frac{5 + 2 \sqrt{3} }{7 + 4 \sqrt{3} } = a - b \sqrt{3} \\ \\ \frac{(5 + 2 \sqrt{3} )}{(7 + 4 \sqrt{3}) } \times \frac{(7 - 4 \sqrt{3})}{(7 - 4 \sqrt{3})} = a - b \sqrt{3} \\ \\ \frac{(5 + 2 \sqrt{3)} (7 - 4 \sqrt{3} )}{ {(7)}^{2} - {(4 \sqrt{3} )}^{2} } a - b \sqrt{3} \\ \\ \frac{35 - 20 \sqrt{3} + 14 \sqrt{3} - 24 }{49 - 48} = a - b \sqrt{3} \\ \\ \frac{11 - 6 \sqrt{3}}{1} = a - b \sqrt{3} \\ \\ 11 - 6 \sqrt{3} = a - b \sqrt{3} \\ \\ equating \: like \: terms \: on \: both \: \\ sides, \: we \: find : \\ \\ a = 11 \\ \\ b = 6$

8 0

3 years ago