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WINSTONCH [101]
3 years ago
14

What is the value of x?ОА. 95°Ов. 1050Ос. 75°OD. 35°​

Mathematics
2 answers:
maxonik [38]3 years ago
4 0
X+70+35=180
X+105. =180. Add like terms
-105. -105. Inverse operations
————————-
X=75
statuscvo [17]3 years ago
3 0
C. 75

70+35+x=180
70+35=105
180-105=75
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Mr. Brown is creating examples of systems of equations. He completes the steps to find the solution of the equation below.
beks73 [17]

Answer:

Option D.

Step-by-step explanation:

The given system of equations is

5x+2y=8    ...(1)

-4(1.25x+0.5y=2)      ...(2)

On simplifying the second equation, we get

-5x-2y=-8

On dividing by -1, we get

5x+2y=8       ...(3)

It is clear that equation (1) and (3) are same equations. It means equation (1) and (2) represent the equivalent equation.

So, the given system of equations has infinitely many solutions.

Therefore, the correct option is D.

6 0
4 years ago
At a track meet, Samma finished the 200-meter race in 25.98 seconds. Tom finished the 100-meter race in 12.54 seconds. Which run
ANEK [815]
Time = distance / speed

Samma : 200/25.98 = 7.70 meters per second
Tom : 100 / 12.54 = 7.97 meters per second

so the faster runner is Tom
8 0
3 years ago
A video game costs $25.00. The sales tax is 7%. How much will the total cost be for the game?
Luba_88 [7]
25 × .07 is the sales tax total
so the sales tax is $1.75
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4 0
3 years ago
Read 2 more answers
A professional basketball team made 37.9% of its three-point field goals in one season. If 80 three-point field goal attempts ar
kompoz [17]

Answer:

The probability that more than 35 were made is 0.14686.

Step-by-step explanation:

We are given that a professional basketball team made 37.9% of its three-point field goals in one season.

80 three-point field goal attempts are randomly selected from the season.

Let \hat p = <em>sample proportion of three-point field goals made in one season.</em>

The z-score probability distribution for the sample proportion is given by;

                           Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }  ~ N(0,1)

where, p = population proprotion of three-point field goals = 37.9% = 0.379

            n = sample of three-point field goal attempts = 80

            \hat p = sample proportion of three-point field goals = \frac{35}{80} = 0.4375

Now, if 80 three-point field goal attempts are randomly selected from the season, the probability that more than 35 were made is given by = P(\hat p > 0.4375)

P(\hat p > 0.4375) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} } > \frac{0.4375-0.379}{\sqrt{\frac{0.4375(1-0.4375)}{80}} } ) = P(Z > 1.05) = 1 - P(Z \leq 1.05)

                                                                       = 1 - 0.85314 = <u>0.14686</u>

The above probability is calculated by looking at the value of x = 1.05 in the z table which has an area of 0.85314.

4 0
4 years ago
Find the selling price of a $15.25 pair of socks with a 18% discount. Round to the nearest cent when necessary.
goldfiish [28.3K]

I believe the answer would be $12.50. multiply the original price and the discount percentage and divide that by 100. once you get the amount saved, which in this case would be $2.75, subtract that from the original price.

4 0
3 years ago
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