Answer: ![Area=5x^2+10x](https://tex.z-dn.net/?f=Area%3D5x%5E2%2B10x)
Step-by-step explanation:
The area of a rectangle:
×![w](https://tex.z-dn.net/?f=w)
![a=5x(x+2)](https://tex.z-dn.net/?f=a%3D5x%28x%2B2%29)
×
× ![2](https://tex.z-dn.net/?f=2)
![a=5x^2+10x](https://tex.z-dn.net/?f=a%3D5x%5E2%2B10x)
-Result:
![a=5x^2+10x](https://tex.z-dn.net/?f=a%3D5x%5E2%2B10x)
The answer is .62
When looking at the diagram given the bar for 8 hours is slightly past .6 but not by much. So the answer is .62
Answer:
Step-by-step explanation:
The point ( -2 , 3) lies in the 2nd quadrant
Point are generally in the form (x , y). The point you need to plot is ( -2 , 3) which means the value of x = -2 and the value of y = 3.
I have attached an image you can check it out.
Answer:
4/5 is the slope of the line represented by the equation y = 4/5x - 3
Step-by-step answer:
Given:
A triangle
Perimeter = 60 cm
longest side = 4* shortest side (x)
Solution:
longest side = 4x
shortest side = x
third (intermediate side = 60 -x -4x = 60-5x
The triangle inequality specifies that the sum of the two shorter sides must be greater than the longest side to form a triangle. Hence
x + y > 4x
x + 60-5x > 4x
60 - 4x > 4x
8x < 60
x < 60/8 = 7.5, or
x < 7.5
Therefore to form a triangle, x (shortest side) must be less than 7.5 cm.
Examine the options: both 7 and 5 are both less than 7.5 cm.
40, 30 and 25 all have a problem because the longest side (4 times longer) will exceed the perimeter of 60.
Now also examine cases where 4x is NOT the longest side, in which case we need
4x>=y
or
4x >= 60-5x
9x >=60
x >= 6.67
so x=5 will not qualify, because 4x will no longer be the longest side.
The only valid option is x=7 cm
The side lengths for x=7 and x=5 are, respectively,
(7, 25, 28)
5, 20, 35 (in which case, the longest side is no longer 4x=20, so eliminated)