All categories

3 years ago

What would be the answer

Mathematics

2 answers:

defon3 years ago

8 0

About 1.5 I’m a math teacher TRUST MY ANSWER wnfkfkgewykkyentwngnnsgngsk1.5 ejfjdjcndnemfmvgmrmrmdmcmrm

MA_775_DIABLO [31]3 years ago

5 0

Mr. Swank van travel about 233. 75 miles with 12. 5 gallons of gasoline ⛽️

You might be interested in

Graph the quadratic function f(x)=2x^2+16x+30 .

kondor19780726 [428]

See the attached picture:

4 0

3 years ago

PLS HELP ASAP!!!<br> domain & range of g(x)?

Morgarella [4.7K]

Domain: (-infinity, +infinity)
range: (0, +infinity)

6 0

3 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

3 years ago

When 27 times x squared times z all over negative 3 times x squared times z to the sixth power is completely simplified, the exp

Volgvan

7

When you do 27 times x squared times z all over -3, then times that by x squared times z to the sixth power, you get -9x^4z^7

6 0

3 years ago

Read 2 more answers

How many revolutions will a car wheel of diameter 22 in. make as the car travels a distance of one mile

Marianna [84]

It would be take upto 999 revolutions.

<em>Let try to solve it,</em>

Let n represent number of revolutions.

We are asked to find the number of revolutions it will take for a car wheel of diameter 30 in. to travel a distance of one mile.

1 mile = 63360 inches.

We will use circumference of circle formula to solve our given problem.

Circumference = pi*d , where, D represents diameter of circle.

Now, we will set the product of n and circumference of circle equal to 63360 inches as:

pi*22*n= 63360

n= 63360*7/ 22*22

n= 443520/444

n= 998.91

Therefore It would be take upto 999 revolutions.

Learn more about Circumference of circle on:

brainly.com/question/18571680

#SPJ4

8 0

2 years ago